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In-s [12.5K]
2 years ago
5

Clear selection

Chemistry
1 answer:
marin [14]2 years ago
8 0

The molarity of the acid given the data from the question is 0.30 M

<h3>Balanced equation </h3>

2HNO₃ + Ba(OH)₂ —> Ba(NO₃)₂ + 2H₂O

From the balanced equation above,

  • The mole ratio of the acid, HNO₃ (nA) = 2
  • The mole ratio of the base, Ba(NO₃)₂ (nB) = 1

<h3>How to determine the molarity of the acid</h3>

From the question given above, the following data were obtained:

  • Volume of acid, HNO₃ (Va) = 39.7 mL
  • Volume of base, Ba(NO₃)₂ (Vb) = 24 mL
  • Molarity of base, Ba(NO₃)₂ (Cb) = 0.250 M
  • Molarity of acid, HNO₃ (Ma) =?

MaVa / MbVb = nA / nB

(Ma × 39.7) / (0.25 × 24) = 2

(Ma × 39.7) / 6 = 2

Cross multiply

Ma × 39.7 = 6 × 2

Ma × 39.7 = 12

Divide both side by 39.7

Ma = 12 / 39.7

Ma = 0.30 M  

Learn more about titration:

brainly.com/question/14356286

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