Answer:
On moon time period will become 2.45 times of the time period on earth
Explanation:
Time period of simple pendulum is equal to 
....eqn 1 here l is length of the pendulum and g is acceleration due to gravity on earth
As when we go to moon, acceleration due to gravity on moon is 
times os acceleration due to gravity on earth
So time period of pendulum on moon is equal to
--------eqn 2
Dividing eqn 2 by eqn 1
So on moon time period will become 2.45 times of the time period on earth
Here is the difference between apparent magnitude and absolute magnitude. When we say apparent magnitude, this is the measurement of the brightness of the star of how it appears on Earth; on the other hand, absolute magnitude is the measurement of the brightness of the star at a <span>standard distance of 32.6 light years, or 10 parsecs. Hope this answers your question.</span>
<span>So what we can do is use the next formula
(<span>Vf</span>)</span>^2=(Vo)^2+2ad
So when we replace the data into the formula it goes
(25)^2 = o^2 + 2(129)a
625 = 258a
a = 2.42 distance/time/time
I hope this helps you
Approx. 983274984065823796374 meters away
