Answer:
W = - 342.70 J
Explanation:
Given:
The mass of the piston, m = 8500 g
Area of the piston, A = 5.50 cm²
initial temperature of the gas, T₁ = 21.0° C = 294 K
Final temperature of the gas, T₂ = 250° C = 523 K
Moles of gas present, n = 0.180 mol
now,
we know
PV = nRT
or
V = nRT/P
where,
P is the pressure
R is the gas constant = 8.314 J / mol. K
V is the volume
Now,
for the initial stage
V₁ = nRT₁/P
and for the final stage
V₂ = nRT₂/P
now, the change in volume is
ΔV = V₂ - V₁
or
ΔV = (nRT₂/P) - (nRT₁/P)
or
ΔV = (1/P)(nR)(T₂ - T₁)
now,
the work done (W) is given as:
W = PΔV
since the work is on the gas, thus
W = - PΔV
on substituting the values, we get
W = - P(1/P)(nR)(T₂ - T₁)
or
W = - (nR)(T₂ - T₁)
on substituting the values in the above equation, we get
W = - (0.180 × 8.314)(523 - 294)
or
W = - 342.70 J
