Answer:
Measurements are an important part of comparing things, as they provide the basis on comparing objects to other objects. Measurements allow us to recognize three hours and see how it's shorter than five hours, without having to observe the hours passing by themselves.
Answer:
0.231 m/s
Explanation:
m = mass attached to the spring = 0.405 kg
k = spring constant of spring = 26.3 N/m
x₀ = initial position = 3.31 cm = 0.0331 m
x = final position = (0.5) x₀ = (0.5) (0.0331) = 0.01655 m
v₀ = initial speed = 0 m/s
v = final speed = ?
Using conservation of energy
Initial kinetic energy + initial spring energy = Final kinetic energy + final spring energy
(0.5) m v₀² + (0.5) k x₀² = (0.5) m v² + (0.5) k x²
m v₀² + k x₀² = m v² + k x²
(0.405) (0)² + (26.3) (0.0331)² = (0.405) v² + (26.3) (0.01655)²
v = 0.231 m/s
There are two external force acts on the chair.
1. The force due to earth gravity, acts in the downward direction.
2. Reaction force of the gravity, which acts in the Upward direction (Normal Force).
On every object, there is a force acts due to gravity of earth, which pulls the object towards the centre of earth, known as gravity force, always acts in the downward direction. Mathematically it's given as
F=mg
here, m is the mass of the object, and g is the acceleration of gravity.
To balance this gravity force, a counter force acts in the opposite direction, whose magnitude is equal to the force of gravity
The tropical rain forest is located mostly on Islands. Mainly found in Africa.
Answer:
A)
B)
C)
D) mosquitoes speed in part B is very much larger than that of part C.
Explanation:
Given:
- Distance form the sound source,
- sound intensity level at the given location,
- diameter of the eardrum membrane in humans,
- We have the minimum detectable intensity to the human ears,
(A)
<u>Now the intensity of the sound at the given location is related mathematically as:</u>
..........................................(1)
<em>As we know :</em>
is the energy transferred to the eardrums per second.
(B)
mass of mosquito,
<u>Now the velocity of mosquito for the same kinetic energy:</u>
(C)
Given:
- Sound intensity,
<u>Using eq. (1)</u>
Now, power:
Hence:
(D)
mosquitoes speed in part B is very much larger than that of part C.