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Thepotemich [5.8K]
3 years ago
8

If there are 50 people per square kilometer in a city, and the area of the city is 1.5 × 10 square kilometers. What is the total

number of people in the city?
Physics
1 answer:
qaws [65]3 years ago
6 0

Answer:

750 people

Explanation:

From the question,

Number of people in the city = population density×Area of the city

N = D×A.......................... Equagtion 1

Where N = Number of people in the city, D = population density, A = Area of the city.

Given: D = 50 people per square kilometer, A = 1.5×10 square kilometer.

Substitute into equation 1

N = 50(1.5×10)

N = 750 people.

Hence the total number of people in the city is 750 people.

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What is the value of work done on an object when a
tino4ka555 [31]
W = F * s
Here, F = 50 N
s = 15 m

Substitute their values, 
W = 50 * 15
W = 750 J

In short, Your Answer would be 750 Joules

Hope this helps!
7 0
3 years ago
What is the gravitational force between two 1 kg objects that are 1 m apart?
lapo4ka [179]

Answer:

F=6.67\times 10^{-11}\ N

Explanation:

Given that,

The masses of two objects, m₁ = m₂ = 1 kg

The distance between masses, d = 1 m

We need to find the gravitational force between two masses. The force is given by the relation as follows :

F=G\dfrac{m_1m_2}{d^2}\\\\F=6.67\times 10^{-11}\times \dfrac{1\times 1}{(1)^2}\\F=6.67\times 10^{-11}\ N

So, the force between two masses of 1 kg is 6.67\times 10^{-11}\ N.

3 0
3 years ago
An ideal gas is maintained at a constant pressure of 70,000 Pa during an isobaric process and its volume decreases by 0.2m^3. Wh
Svetach [21]

Answer:

c. -14,000

Explanation:

Workdone by gas is the product of the pressure and the volume where there is a change of volume.

If v1 is the initial volume of the gas and v2 is the final volume of gas, the work done

= p(v2 - v1)

where p is the pressure

and p = 70,000 Pa

Given that volume decrease by 0.2m^3, v2 - v1 = -0.2

Workdone = 70000 ( -0.2)

Workdone = -14,000 J

Option c. -14,000

5 0
4 years ago
The objects listed are placed at the top of a ramp and roll down to the bottom without slipping. Assuming that there is no air r
Thepotemich [5.8K]

Explanation:

For each object, the initial potential energy is converted to rotational energy and translational energy:

PE = RE + KE

mgh = ½ Iω² + ½ mv²

For the marble (a solid sphere), I = ⅖ mr².

For the basketball (a hollow sphere), I = ⅔ mr².

For the manhole cover (a solid cylinder), I = ½ mr².

For the wedding ring (a hollow cylinder), I = mr².

If we say k is the coefficient in each case:

mgh = ½ (kmr²) ω² + ½ mv²

For rolling without slipping, ωr = v:

mgh = ½ kmv² + ½ mv²

gh = ½ kv² + ½ v²

2gh = (k + 1) v²

v² = 2gh / (k + 1)

The smaller the value of k, the higher the velocity.  Therefore:

marble > manhole cover > basketball > wedding ring

7 0
4 years ago
A 4400 W motor is used to do work. If the motor is used for 200 s, how much work could it do? (Power: P = W/t)
Inga [223]
Hope this helps, have a great day ahead!

7 0
3 years ago
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