Part a can be solve using the equation of trajectory:
Y = x tana + (g*x^2)/ [2(V0^2)*(cos a)^2]
Where y is the height
X is the length
G is the acceleration due to gravity
Vo Is the initail velocity
a is the angle of trajectory
1.2 = 1.35 tan(0) +
(9.81*1.35^2)/ [2(V0^2)*(cos 0)^2]
Solve for V0 = 2.729 m/s
b. can be solve using the formula
v = sqrt(2gy)
= sqrt ( 2*1.2*9.81)
= 4.852 m/s going
down ( 0 degree from the horizontal)
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Answer:
(Example Person) has to push hard to get the skateboard started, but once it begins moving, it takes much less effort to keep it rolling over the smooth, flat pavement. In fact, if (Example Person) tries to stop the rolling skateboard, it may take as much effort to stop it as it did to start it rolling in the first place.
Explanation:
Hope this helps :)
Answer:
Wave A.
Explanation:
The energy of a wave is directly proportional to the square of the amplitude.
If a wave has higher amplitude, it will have more energy. On the other hand, a wave having lower amplitude, it will have less eenergy.
In this case, we need to tell which wave has higher energy. Hence, the correct option is A because it has a higher amplitude.
Answer:
9266 feet
Explanation:
with Earth's gravity and long it fell that's as good as it gets if there was no other factors like wind mass weight but your welcome
The bicyclist accelerates with magnitude <em>a</em> such that
25.0 m = 1/2 <em>a</em> (4.90 s)²
Solve for <em>a</em> :
<em>a</em> = (25.0 m) / (1/2 (4.90 s)²) ≈ 2.08 m/s²
Then her final speed is <em>v</em> such that
<em>v</em> ² - 0² = 2<em>a</em> (25.0 m)
Solve for <em>v</em> :
<em>v</em> = √(2 (2.08 m/s²) / (25.0 m)) ≈ 10.2 m/s
Convert to mph. If you know that 1 m ≈ 3.28 ft, then
(10.2 m/s) • (3.28 ft/m) • (1/5280 mi/ft) • (3600 s/h) ≈ 22.8 mi/h
