Answer:
money deposited after end of 3rd year is $4877.75
Explanation:
given data
initial amount = $10000
rate = 5%
time = 3 year
after 7 year account balance = $20000
solution
we consider here money deposited after end of 3rd year is = x
first we get here compounded amount after 3 years as
compounded amount = initial amount ×
................1
compounded amount = 10000 ×
compounded amount = $11576.25
so at 7 year account balance is
account balance = ( compounded amount + x ) ×
....................2
$20000 = ( $11576.25 + x ) ×
solve it we get
x = $4877.75
so money deposited after end of 3rd year is $4877.75
Answer:
1. T=19.5n+91.75, where n<70
2. T=15n+45, where n≥70
Explanation:
1. The first linear function can be expressed as;
Total cost of catering services=(Cost per person×number of people, n)+Service charge
where;
Total cost of catering services=T
Cost per person=$19.50
Number of people=n
Service charge=$91.75
Replacing;
T=(19.5×n)+91.75
T=19.5n+91.75
The first equation: T=19.5n+91.75, where n<70
2. The second linear function can be expressed as;
Total cost of catering services=(Cost per person×number of people, n)+Service charge
where;
Total cost of catering services=T
Cost per person=$15
Number of people=n
Service charge=$45
Replacing;
T=(15×n)+45
T=15n+45
The second equation: T=15n+45, where n≥70
Answer:
The correct response is "145,000
".
Explanation:
The given values are:
Purchased cost,
= $150,000
Expenses,
= $5,000
Selling cost,
= $10,000
Now,
Logan's basis for depreciation will be:
= 
On putting the values, we get
= 
= 
=
($)