The correct answer is (c) It would have lower ionization energies than K and a lower electronegativity value than K
Explanation- The unknown element belongs to the alkali metals of periodic table. The alkali metal atoms have the largest size in a particular period of the period of periodic table. With the increase in the atomic number, the atom becomes larger.
Atomic radius decreases --> ionization energy increase---->Electronegativity increases. We can use this flow chart to compare the IE and EN of the element. As K have lower radii than the unknown element, so the IE and EN of K will be greater than the unknown element.
Because the solid is soluble in water, it cannot be calcium fluoride.
This leaves us with either silver fluoride or potassium bromide, as both are soluble in water.
Upon addition of sodium sulfate, a white precipitate forms, confirming that the substance was silver fluoride as the precipitate are of silver sulfate.
Answer:
0.136g
Explanation:
A student dissolved 5.00 g of Co(NO3)2 in enough water to make 100. mL of stock solution. He took 4.00 mL of the stock solution and then diluted it with water to give 275. mL of a final solution. How many grams of NO3- ion are there in the final solution?
Initial mole of Co(NO3)2 
Mole of Co(NO3)2 in final solution
Mole of NO3- in final solution = 2 x Mole of Co(NO3)2
Mass of NO3- in final solution is mole x Molar mass of NO3
Answer:
The correct answer is "more fluid bilayers".
Explanation:
A fatty acid is a biomolecule of lipidic nature formed by a long hydrocarbon chain of different lengths at the end of which there is a carboxyl group.
The wall of the gallbladder consists of three main layers of tissue: The mucosa covers the wall of the gallbladder. The muscular layer of smooth muscle. The serosa, which is the outer layer.
By decreasing the saturation of the fatty acid chains in phospholipids, the bile layers would reduce their thickness and become more fluid.
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Answer:
sodium chloride is produced= Na+ Cl⇒ NaCl
Explanation: when sodium reacts with chlorine, sodium gives out its electron to chlorine for them to become stable. in the end they form an ionic compound known as sodium chloride
