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2 years ago

Word or symbol used to describe how data was measured

Chemistry

1 answer:

Orlov [11]2 years ago

5 0

Answer:

Unit

Explanation:

Unit is used to describe how data is measured.

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5. A 5.00 g sample of an unknown substance was heated from 25.2 C to 55.1 degrees * C , and it required 133 to do so. Identify t

Leviafan [203]

Answer:

Aluminum

Explanation:

Given

$T_1 = 25.2^oC$

$T_2 = 55.1^oC$

$m = 5.00g$

$\triangle Q= 133J$

See attachment for chart

Required

Identify the unknown substance

To do this, we simply calculate the specific heat capacity from the given parameters using:

$c = \frac{\triangle Q}{m\triangle T}$

This gives:

$c = \frac{\triangle Q}{m(T_2 - T_1)}$

So, we have:

$c = \frac{133J}{5.00g * (55.1C - 25.2C)}$

$c = \frac{133J}{5.00g * 29.9C}$

$c = \frac{133J}{149.5gC}$

$c = 0.89\ J/gC$

From the attached chart, we have:

$Al(s) = 0.89\ J/gC$ --- The specific heat capacity of Aluminum

Hence, the unknown substance is Aluminum

7 0

3 years ago

Which statement is true according to the kinetic theory?

Vlad [161]

Answer:

Molecules of different gases with the same mass and temperature always have the same average kinetic energy - E.

5 0

3 years ago

Read 2 more answers

Give three examples of heterogeneous mixtures and three examples of solutions that you might use in everyday life.

beks73 [17]

Answer:

Explanation:

Heterogeneous mixtures: Milk, salt and pepper, smog, chocolate chip cookie, oil and water.

Solutions we might use everyday: Gatorade, Apple Juice, most wines and liquor, liquid detergent, coffee etc.

7 0

3 years ago

olya-2409 [2.1K]

The answer is head-to-tail joining of monomers. Monomer used in condensation have two functional groups that combine to form amide and ester linkages. When this reaction occurs, water molecules is removed and that is why it is called a condensation reaction.

8 0

3 years ago

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What volume of CH4(g), measured at 25oC and 745 Torr, must be burned in excess oxygen to release 1.00 x 106 kJ of heat to the su

anastassius [24]

Answer:

$V=27992L=28.00m^3$

Explanation:

Hello,

In this case, the combustion of methane is shown below:

$CH_4+2O_2\rightarrow CO_2+2H_2O$

And has a heat of combustion of −890.8 kJ/mol, for which the burnt moles are:

$n_{CH_4}=\frac{-1.00x10^6kJ}{-890.8kJ/mol}= 1122.6molCH_4$

Whereas is consider the total released heat to the surroundings (negative as it is exiting heat) and the aforementioned heat of combustion. Then, by using the ideal gas equation, we are able to compute the volume at 25 °C (298K) and 745 torr (0.98 atm) that must be measured:

$PV=nRT\\\\V=\frac{nRT}{P}=\frac{1122.6mol*0.082\frac{atm*L}{mol*K}*298K}{0.98atm}\\\\V=27992L=28.00m^3$

Best regards.

8 0

3 years ago