Yes, very informational. thank you.
Answer:
No it is not because it is not in group 3 or 12.
Explanation:
The numerical value of Kc is 1.129 x10^4
<u><em> Explanation</em></u>
C3H6O +4O2→ 3 CO2 + 3H2O
KC is the ratio of concentration of the product over the reactant.
Each concentration of product and reactant are raised to the power of its coefficient.
Therefore the KC expression of equation above is
Kc=[ (Co2)^3 (H2O)^3] / [(C3H6O) (O2)^4)]
Kc =[(1.8^3) x (2.0^3)] / [(0.51) x (0.30^4)] =1.129 x10^4
Since there are no conversions to be done just add them as is
a) 1 g
b) 1.0 kg
c) 22 L
d) 3.6 cm
<span>e) 104.9 g</span>
Answer:
a) ionic b) polar covalent c) nonpolar covalent
Explanation:
To determine if a bond is covalent or ionic without knowing the electronegativities is to see if it is a metal-nonmetal bond or a nonmetal-nonmetal bond. Metal-nonmetal bonds are ALWAYS ionic, and nonmetal-nonmetal bonds are ALWAYS covalent. A is the metal-nonmetal bond and thus ionic. B & C are both nonmetal-nonmetal bonds and thus covalent.
Polarity:
To determine if a covalent bond is polar or not, we need to see how far apart the elements are away from one another. The further away the elements are from one another the more polar the bond. Nonmetal elements bonded to themselves are ALWAYS nonpolar see compound C. For B, the elements are far apart and are still covalent, so these bonds are polar.
