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iris [78.8K]
3 years ago
15

Describe how to draw a 3-heptyne

Chemistry
1 answer:
lesantik [10]3 years ago
3 0
You can't really describe it but this is what it looks like http://www.chemspider.com/Chemical-Structure.453291.html
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A sample of 211 g of iron (III) bromide is reacted with
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FeBr₃ ⇒ limiting reactant

mol NaBr = 1.428

<h3>Further explanation</h3>

Reaction

2FeBr₃ + 3Na₂S → Fe₂S₃ + 6NaBr

Limiting reactant⇒ smaller ratio (mol divide by coefficient reaction)

  • FeBr₃

211 g of Iron (III) bromide(MW=295,56 g/mol), so mol FeBr₃ :

\tt n=\dfrac{mass}{MW}\\\\n=\dfrac{211}{295,56}\\\\n=0.714

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186 g of Sodium sulfide(MW=78,0452 g/mol), so mol Na₂S :

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\tt FeBr_3\div Na_2S=\dfrac{0.714}{2}\div \dfrac{2.38}{3}=0.357\div 0.793

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\tt \dfrac{6}{3}\times 0.714=1.428

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3 years ago
If an ideal gas at a constant temperature is initially at a pressure of 3.8 atm and is then allowed to expand to a volume of 5.6
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