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Brums [2.3K]
3 years ago
10

How often do most coastlines on Earth experience two high tides and two low tides?

Chemistry
1 answer:
Elza [17]3 years ago
4 0

Answer:

24 hours and 50 minutes

Explanation:

Because the Earth rotates through two tidal “bulges” every lunar day, coastal areas experience two high and two low tides every 24 hours and 50 minutes. High tides occur 12 hours and 25 minutes apart. It takes six hours and 12.5 minutes for the water at the shore to go from high to low, or from low to high.

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Yes the answer is correct the plant uses the energy to grow and fertilize other plants
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Sulfuric acid dissolves aluminum metal according to the following reaction: 2Al(s)+3H2SO4(aq)→Al2(SO4)3(aq)+3H2(g)2Al(s)+3H2SO4(
ryzh [129]

Answer:

83.9g of sulfuric acid is the minimum mass you would need

1.73g of hydrogen would be produced

Explanation:

Based on the reaction:

2 Al(s) + 3 H₂SO₄(aq) → Al₂(SO₄)₃(aq) + 3 H₂(g)

2 moles of solid aluminium react with 3 moles of sulfuric acid. Also, two moles of Al produce 3 moles of hydrogen gas.

15.4g of Al are:

15.4g Al × (1mol / 26.98g) = 0.571 moles of Al.

Moles of sulfuric acid:

0.571 moles Al × (3 mol H₂SO₄ / 2 mol Al) = 0.8565 moles H₂SO₄

In grams:

0.8565 moles H₂SO₄ × (98g / 1mol) = <em>83.9g of sulfuric acid is the minimum mass you would need</em>

In the same way, moles of hydrogen produced are:

0.571 moles Al × (3 mol H₂ / 2 mol Al) = 0.8565 moles H₂

In grams:

0.8565 moles H₂ × (2.015g / 1mol) = <em>1.73g of hydrogen would be produced</em>

3 0
3 years ago
Using the periodic table in your textbook, calculate the molar mass of paraffin (C46H92O2).
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Answer:

677.39 g/mol

Explanation:

Step 1: Find molar masses of elements

Carbon (C) - 12.01 g/mol

Hydrogen (H) - 1.01 g/mol

Oxygen (O) - 16.00 g/mol

Step 2: Multiply the amount present

12.01 g/mol · 46 = 552.46 g/mol

1.01 g/mol · 92 = 92.92 g/mol

16.00 g/mol · 2 = 32.00 g/mol

Step 3: Add up all the molar masses to find compound molar mass

552.46 g/mol + 92.92 g/mol + 32.00 g/mol = 677.39 g/mol

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