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3 years ago

How often do most coastlines on Earth experience two high tides and two low tides?

Chemistry

1 answer:

Elza [17]3 years ago

4 0

Answer:

24 hours and 50 minutes

Explanation:

Because the Earth rotates through two tidal “bulges” every lunar day, coastal areas experience two high and two low tides every 24 hours and 50 minutes. High tides occur 12 hours and 25 minutes apart. It takes six hours and 12.5 minutes for the water at the shore to go from high to low, or from low to high.

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50 POINTS!!!

Galina-37 [17]

The condition or progress of a reaction is represented by reaction arrows. The chemical reaction arrow is a single straight arrow that points from the reactant(s) to the product(s) and by-products, as well as side products.

I think this should help you find the answer more easy!

6 0

3 years ago

Read 2 more answers

What is the approximate percentage of corn syrup that would make an isotonic solution for the egg?

My name is Ann [436]

This can be answered when you execute the egg osmosis sample. All you have to do is submerge the egg in the corn syrup. Since the corn syrup is more concentrated than the egg, the solute would pass through the egg's cellular membrane. In exchange, the water from the egg would go to the syrup. It will achieve equilibrium when both the egg and the corn syrup would have equal osmotic pressures. <em>The solution would be isotonic at approximately 42% corn syrup.</em>

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4 years ago

A solution is made by dissolving 0.565 g of potassium nitrate in enough water to make up 250. mL of solution. What is the molari

aalyn [17]

<h3>Molar mass of Potassium Nitrate:-</h3>

$\\ \large\sf\longmapsto KNO_3$

$\\ \large\sf\longmapsto 39u+14u+3(16u)$

$\\ \large\sf\longmapsto 53u+48u$

$\\ \large\sf\longmapsto 101u$

$\\ \large\sf\longmapsto 101g/mol$

Now

$\boxed{\sf No\:of\:moles=\dfrac{Given\:mass}{Molar\:mass}}$

$\\ \large\sf\longmapsto No\:of\:moles=\dfrac{0.565}{101}$

$\\ \large\sf\longmapsto No\:of\:moles=0.005mol$

We know

$\boxed{\sf Molarity=\dfrac{Moles\:of\:solute}{Vol\:of\:Solution\:in\:L}}$

$\\ \large\sf\longmapsto Molarity=\dfrac{0.005}{\dfrac{250}{1000}L}$

$\\ \large\sf\longmapsto Molarity=\dfrac{0.005}{0.250}$

$\\ \large\sf\longmapsto Molarity=0.02M$

8 0

3 years ago

Read 2 more answers

Definition: This is the male reproductive cell.

Mamont248 [21]

The answer would be Sperm.

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3 years ago

How many grams of O2 are needed to react with 8.15 g of C2H2?

xxTIMURxx [149]

Answer:

25.08 grams of O₂ are needed to react with 8.15 g of C₂H₂.

Explanation:

The balanced reaction is:

2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O

By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:

C₂H₂: 2 moles
O₂: 5 moles
CO₂: 4 moles
H₂O: 2 moles

The molar mass of each compound is:

C₂H₂: 26 g/mole
O₂: 32 g/mole
CO₂: 44 g/mole
H₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

C₂H₂: 2 moles* 26 g/mole= 52 g
O₂: 5 moles* 32 g/mole= 160 g
CO₂: 4 moles* 44 g/mole= 176 g
H₂O: 2 moles* 18 g/mole= 36 g

Then you can apply the following rule of three: if by stoichiometry 52 grams of C₂H₂ react with 160 grams of O₂, 8.15 grams of C₂H₂ react with how much mass of O₂?

$mass of O_{2} =\frac{8.15 grams of C_{2} H_{2}*160 grams of O_{2} }{52 grams of C_{2} H_{2}}$

mass of O₂= 25.08 grams

<u><em>25.08 grams of O₂ are needed to react with 8.15 g of C₂H₂.</em></u>

8 0

3 years ago