1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dmitrij [34]
3 years ago
15

Stars release huge amounts of radiation from their surfaces while on the main sequence. why is this necessary if a star is to ma

intain hydrostatic equilibrium?
Physics
1 answer:
kotegsom [21]3 years ago
8 0
Hydrostatic equilibrium is the energy balance between two forces at the stars: the inward force of gravity (<span>due to the </span>mass<span> of the star) </span>and the outward gas pressure (due to the energy release from nuclear reactions in the core of the star). Hydrostatic equilibrium is important because it holds the star together.
You might be interested in
At which part of its orbit is the planet traveling at the slowest speed?<br> A, B, C, or D
Natali [406]
I think its D im not sure tho
3 0
3 years ago
Read 2 more answers
Approximately how much air is in a column 1-cm2 in cross section that extends from sea level to the top of the atmosphere?
laila [671]

Approximately 101 N air is in a column 1-cm2 in cross-section that extends from sea level to the top of the atmosphere

The basic level for determining height and depth on Earth is the sea level. The ocean's surface tends to seek the same level since it is one continuous body of water. However, the sea level is never fully level due to winds, currents, river discharges, and changes in gravity and temperature.

At the equator, the radius of the Earth at sea level is 6378.137 km (3963.191 mi). At the poles, it is 6,356.752 km (3,949.903 km), and on average, it is 6,371.001 km (3,958.756 mi). The elevation of the shoreline—the boundary between the ocean and the land—is referred to as sea level. Land that is higher than this altitude is above sea level, and land that is lower is below sea level.

To learn more about sea level please visit -
brainly.com/question/2113249
#SPJ4

8 0
2 years ago
A satellite of mass m orbits a moon of mass M in uniform circular motion with a constant tangential speed of v. The gravitationa
lukranit [14]

Answer:

Two stars, each of mass M, form a binary system. ... used is the distance between the centers of the planets; here that distance is 2R. ... r appears in the denominator of Newton's law of gravitation, the force of ... The orbital speed of a satellite orbiting the earth in a circular orbit at the ... is undergoing uniform circular motion?

Explanation:

Two stars, each of mass M, form a binary system. ... used is the distance between the centers of the planets; here that distance is 2R. ... r appears in the denominator of Newton's law of gravitation, the force of ... The orbital speed of a satellite orbiting the earth in a circular orbit at the ... is undergoing uniform circular motion?

3 0
3 years ago
A motorist enters a freeway at 45 km/h and accelerates uniformly to 99 km/h. From the odometer in the car, the motorist knows th
Marat540 [252]

Answer:

a)  19440 km/h²

b) 10 sec

Explanation:

v₀ = initial velocity of the car = 45 km/h

v = final velocity achieved by the car = 99 km/h

d = distance traveled by the car while accelerating = 0.2 km

a = acceleration of the car

Using the kinematics equation

v² = v₀² + 2 a d

99² = 45² + 2 a (0.2)

a = 19440 km/h²

b)

t = time required to reach the final velocity

Using the kinematics equation

v = v₀ + a t

99 = 45 + (19440) t

t = 0.00278 h

t = 0.00278 x 3600 sec

t = 10 sec

5 0
3 years ago
A 40 kg girl and an 8.4 kg sled are on the surface of a frozen lake, 15 m apart. By means of a rope, the girl exerts a 5.2 N for
stealth61 [152]

Answer:

(a) a_s=0.62\frac{m}{s^2}

(b) a_s=0.13\frac{m}{s^2}

(c) x_f=2.6m

Explanation:

(a) According to Newton's second law, the acceleration of a body is directly proportional to the force exerted on it and inversely proportional to it's mass.

a_s=\frac{F}{m_s}\\a_s=\frac{5.2N}{8.4kg}\\a_s=0.62\frac{m}{s^2}

(b) According to Newton's third law, the force that the sled exerts on the girl is equal in magnitude but opposite in the direction of the force that the girl exerts on the sled:

a_g=\frac{F}{m_g}\\a_g=\frac{5.2N}{40kg}\\a_g=0.13\frac{m}{s^2}

(c) Using the kinematics equation:

x_f=x_0+v_0t \pm  \frac{at^2}{2}

For the girl, we have x_0=0 and v_0=0. So:

x_f_g=\frac{a_gt^2}{2}(1)

For the sled, we have v_0=0. So:

x_f_s=x_0_s-\frac{a_st^2}{2}(2)

When they meet, the final positions are the same. So, equaling (1) and (2) and solving for t:

x_0_s-\frac{a_st^2}{2}=\frac{a_st^2}{2}\\t^2(a_g+a_s)=2x_0_s\\t=\sqrt{\frac{2x_s_0}{a_g+a_s}}\\t=\sqrt{\frac{2(15m)}{0.13\frac{m}{s^2}+0.62\frac{m}{s^2}}}\\t=6.32s

Now, we solve (1) for x_f_g

x_f_g=\frac{0.13\frac{m}{s^2}(6.32s)^2}{2}\\x_f_g=2.6m\\x_f=2.6m

5 0
3 years ago
Other questions:
  • Near the end of a marathon race, the first two runners are separated by a distance of 45.6 m. The front runner has a velocity of
    15·1 answer
  • A student stands on a bathroom scale in an elevator at rest on the 64th floor of a building. The scale reads 836 N.
    11·1 answer
  • How do very high density objects appear in an ultrasound?
    6·1 answer
  • Please help I'm taking a timed test!
    15·2 answers
  • Two runners start simultaneously from the same point on a circular 200-m track and run in the same direction. One runs at a cons
    6·1 answer
  • . A 79 g sample of water at 21oC is heated until it becomes steam with a temperature of 143oC. Find the change in heat content o
    9·1 answer
  • Is work being done on a barbell when a weight lifter is holding the barbell<br> over his head?
    7·1 answer
  • Plz help with this<br> And thanks
    14·2 answers
  • Which element does not have the same number of electrons in its outermost shell as the other elements in its group?(1 point)
    14·2 answers
  • PLEASE HURRY, I'M BEING TIMED!
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!