Stars release huge amounts of radiation from their surfaces while on the main sequence. why is this necessary if a star is to ma
1 answer:
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Answer:
0.28802
2.57162 W
14.28 W
53.55 W
6.07142 W
Explanation:
R = 280Ω
L = 100 mH
C = 0.800 μF
V = 50 V
ω = 10500rad/s
For RLC circuit impedance is given by
Power factor is given by
The power factor is 0.28802
The average power to the circuit is given by
The average power to the circuit is 2.57162 W
Power to resistor
Power to resistor is 14.28 W
Power to inductor
Power to the inductor is 53.55 W
Power to the capacitor
The power to the capacitor is 6.07142 W
Here in this case we can use work energy theorem
As per work energy theorem
Work done by all forces = Change in kinetic Energy of the object
Total kinetic energy of the solid sphere is ZERO initially as it is given at rest.
Final total kinetic energy is sum of rotational kinetic energy and translational kinetic energy
also we know that
Now kinetic energy is given by
Now by work energy theorem
Work done = 10500 - 0 = 10500 J
So in the above case work done on sphere is 10500 J