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3 years ago

Look carefully at the diagrams of each wave.

Physics

2 answers:

Alexxandr [17]3 years ago

6 0

wave b has the shortest wave length

lilavasa [31]3 years ago

3 0

Answer : Wave B.

Explanation :

Given that, the waves A, B, C, and D each represent a different wave of the electromagnetic spectrum.

The energy of a wave is given by :

$E=\dfrac{hc}{\lambda}$

Where,

h is the Planck constant

c is the speed of the light

$\lambda$ is the wavelength of light.

The wavelength of a wave is defined as the distance between two consecutive crests or troughs.

The energy of the wave is inversely proportional to its wavelength.

So, the wave that is energetic enough to damage living human cells is wave B because its wavelength is small as compared to other waves.

<em>Hence, the correct option is (B) " Wave B because it has the shortest wavelength, and therefore carries the most energy ". </em>

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Which phase of matter contains particles that split into ions and electrons?

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Answer:

Plasma

Explanation:

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3 years ago

For an object to slow down and stop due to friction while sliding across the floor which of the following would be true.

EastWind [94]

Answer:10-4

Explanation:

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3 years ago

A particle with a charge of 5 × 10–6 C and a mass of 20 g moves uniformly with a speed of 7 m/s in a circular orbit around a sta

creativ13 [48]

Answer:

r = 0.22m

Explanation:

To find the radius of the circular trajectory, you first take into account that the centripetal force of the charged particle, is equal to the electric force between the particle that is moving and the particle at the center of the orbit.

Then, you have:

$F_c=F_e=ma_c$ (1)

m: mass of the particle = 20g = 20*10-3 kg

ac: centripetal acceleration = ?

q: charge of the particle = 5*10^-6C

Fe: electric force between the charges

The electric force is given by:

$F_e=k\frac{qq'}{r^2}$ (2)

r: radius of the orbit

q': charge of the particle at the center of the orbit = -5*10^-6C

Furthermore, the centripetal acceleration is:

$a_c=\frac{v^2}{r}$ (3)

v: speed of the particle = 7m/s

You replace the expressions (2) and (3) in the equation (1) and solve for r:

$k\frac{qq'}{r^2}=m\frac{v^2}{r}\\\\r=\frac{kqq'}{mv^2}$

Finally, you replace the values of all parameters in the previous expression:

$r=\frac{(8.98*10^9Nm^2/C^2)(5*10^{-6}C)(5*10^{-6}C)}{(20*10^{-3}kg)(7m/s)^2}\\\\r=0.22m$

The radius of the circular trajectory is 0.22m

5 0

3 years ago

what will happen to the pressure in a gas if you compressed it into a volume that was one third the size? why?

Annette [7]

Answer:

Pressure will triple (Boyle's Law)

Explanation:

Assuming a constant temperature: (compressing gases usually raises the temp significantly):

P1V1 = P2V2

P1V1 / V2 = P2

Now change V2 to 1/3 V2:

P1V1 / (1/3 V2 ) = P2 / (1/3 )

P1V1/ (1/3 v2 ) = 3 P2 <======= THE PRESSURE WILL TRIPLE

This is Boyle's Law

5 0

2 years ago

An ideal gas is brought through an isothermal compression process. The 3.00 mol 3.00 mol of gas goes from an initial volume of 2

ozzi

Answer:

The answers can be found by considering the isothermal expansion equation as well as the ideal gas equation from where we have

The temperature T = 602.64K and the final pressure P = 110.24MPa

Explanation:

Numbeer of moles of gas = 3.00 mol

initial volume = 230.8×10−6 m3

final volume = 133.4×10−6 m3 .

released energy = 8240 J

Temperature = Constant = T

Pressure = $p_{f}$ =unknown

From the relation the combined ideal gas law, PV = nRT

Where R = 8.314 4621.JK−1mol−1

we have The release energy from compression P1V1 -P2V2

-qrev = -nRTln( $\frac{V_{2} }{V_{1} }$ ) = 8240J

n = 3

Hence -nRTln( $\frac{V_{2} }{V_{1} }$ ) = 3×8.314 462×ln $(\frac{133.4}{230.8})$ × T= -8240 J

or -13.67×T = -8240J, thus T = -8240/-13.67 = 602.64K

The Final pressure is given by

PV = n×R×T from where we have V = final volume thus

P = (n×R×T)/V = (3×8.134×602.64)÷(133.4× $10^{-6}$ ) = 110237041.1 N/ $m^{2}$ = 110.237MPa

8 0

3 years ago