All categories

3 years ago

Which of the following is a synthesis reaction?

Chemistry

2 answers:

Brums [2.3K]3 years ago

5 0

Answer:

C) SO3 + H2O → H2SO4

Explanation:

Took the test, this is the answer.

kirill115 [55]3 years ago

3 0

I believe that the answer is either B or C, because a synthesis reaction is when A+B→AB, so A and D cannot be correct, hope this helps some.

You might be interested in

What is homogeneous mixture?

Nataly [62]

A mixture is a portion of matter made up of two or more substances called constituents. Mixtures are the product of the mechanical joining of substances without change in chemical nature, and therefore, each constituent retains its properties.

the option 4

4 0

3 years ago

How much heat is needed to melt 10.0 grams of ice at -10°C until it is water at 10°C?

zhannawk [14.2K]

The heat needed to melt 10.0 grams of ice at -10°C until it is water at 10°C is 3,969.5 J. (approx= 3963J).

<h3>What is Sensible heat? </h3><h3 />

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state.

Q= c×m×∆T

<h3>What is Latent heat? </h3><h3 />

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

In this case, the heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q= m×L

Where,

L is the latent heat

C= specific heat capacity of ice= 2.108 J/gK

M= 10 g

ΔT= T(final)– T(initial) = 0 °C – (-10 °C)= 10 °C= 10 K

Sensitive heat Q(1) = 2.108×10×10

= 210.8J

<h3>Heat needed to melt ice</h3><h3 />

The specific heat of melting of ice is 334 J/g, the heat needed to melt 10 grams of ice is

Q(2) = 10× 334

= 3340J

C= specific heat capacity of liquid water is 4.187 J/gK

M= 10 g

ΔT= T(final) – T(initial) = 10 °C – 0 °C= 10 °C= 10 K because being a temperature difference, the difference is the same in °C and K.

Q(3) = 4.187×10×10

= 418.7 J.

Total heat required= Q1 + Q2 + Q3

Total heat required= 210.8 J + 3,340 J + 418.7 J

= 3969.5J

Thus, the heat needed to melt 10 gram of ice from temperature-10°C to 10°C is 3969.5. Therefore, option B is correct option.

learn more about heat :

brainly.com/question/16818736

#SPJ1

8 0

2 years ago

How many grams of CaCl2 are in 250 mL of 2.0 M CaCl2?

Tom [10]

The answer is:  " 56 g CaCl₂ " .
__________________________________________________________

Explanation:
__________________________________________________________
2.0 M CaCl₂ = 2.0 mol CaCl₂ / L ;

Since: "M" = "Molarity" (measurement of concentration);

= moles of solute per L {"Liter"} of solution.
__________________________________________________________
Note the exact conversion: 1000 mL = 1 L .

Given: 250 mL ;

250 mL = ? L ? ;

250 mL * (1 L / 1000 L) = (250/1000) L = 0.25 L .
___________________________________________________________

(2.0 mol CaCl₂ / L ) * (0.25L) = (2.0) * (0.25) mol  = 0.50 mol CaCl₂ ;

We have: 0.50 mol CaCl₂ ; Convert to "g" (grams):

→ 0.50 mol CaCl₂ .
___________________________________________________________
1 mol CaCl₂ = ? g ?

From the Periodic Table of Elements:

1 mol Ca = 40.08 g

1 mol Cl = <span>35.45 g .
</span>
There are 2 atoms of Cl in " CaCl₂ " ;

→ Note the subscript, "2", in the " Cl₂ " ;
__________________________________________________________
So, to calculate the molar mass of "CaCl₂" :

40.08 g + 2(35.45 g) =

40.08 g + 70.90 g = 110.98 g ; round to 4 significant figures;

→ round to 111 g/mol .
__________________________________________________________
So:

→ 0.50 mol CaCl₂ = ? g CaCl₂ ? ;

→ 0.50 mol CaCl₂ * (111 g CaCl₂ / mol CaCl₂) ;

= (0.50) * (111 g) CaCl₂ ;

= 55.5 g CaCl₂ ;

  → round to 2 significant figures;

  → 56 g CaCl₂ .
___________________________________________________________
The answer is: " 56 g CaCl₂ " .
___________________________________________________________

6 0

3 years ago

Read 2 more answers

Enter the ions formed when (NH4)2S dissolves in water.

lisabon 2012 [21]

The ions formed are NH4(+) and S(2-)

The dissolution reaction of (NH4) 2S in water is as follows:

(NH4) 2S ==> 2 NH4 (+) + S (2-).

Ammonium sulfide is the ammonium salt of hydrogen sulfide. It has the formula (NH4) 2S and belongs to the sulfide family.

It is a relatively unstable compound (crystals decomposing at -18 ° C, but exists and is more stable in aqueous solution.) With a pKa exceeding 15, the hydrosulfide ion cannot be significantly deprotonated by ammonia. Thus, such solutions consist mainly of a mixture of ammonia and hydrosulphide of ammonium, it has a smell, close to that of hydrogen sulfide, and its aqueous solutions can be precisely by emitting H2S.

5 0

3 years ago

Read 2 more answers

reativity of alkali metals increases down the group while reativity decreases down the group in helogens

BigorU [14]

Complete question is;

Chemical reactivity of alkali metals increases down the group while reactivity of halogens decreases down the group. Give reasons

Answer:

Explained below

Explanation:

Alkali metals exhibit reactivity due to their electropositivity. Now, for alkalis, their electro-positivity increases down their group. Since their reactivity increases with increase in electropositivity, it means their reactivity also increases down the group.

Whereas, the reactivity of halogens occurs as a result of their electronegativity. Now, electronegativity for halogens decreases down the group. Since their reactivity decreases with decrease in electronegativity, it means that their reactivity will also decrease down the group.

4 0

3 years ago