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3 years ago

What is its molar heat of vaporization in kilojoules per mole if its vapor pressure at 20°C is 11.0 torr?

Chemistry

1 answer:

NemiM [27]3 years ago

7 0

Answer:

H.vap = 6.544 kJ/mol

Explanation:

Clausius-Clapeyron Equation

In P = H.vap / RT where T = 20 + 273 = 293K

H.vap = In P (RT) = In 11 (8.314 x 293) = 6543.861 J/mol = 6.544 kJ/mol

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Answer:

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Explanation:

The reaction that takes place is:

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3 years ago

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Answer:

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