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kumpel [21]
3 years ago
12

What is its molar heat of vaporization in kilojoules per mole if its vapor pressure at 20°C is 11.0 torr?

Chemistry
1 answer:
NemiM [27]3 years ago
7 0

Answer:

<em>H.vap = 6.544 kJ/mol</em>

Explanation:

Clausius-Clapeyron Equation

<em>In P = H.vap / RT</em> where T = 20 + 273 = 293K

H.vap = In P (RT) = In 11 (8.314 x 293) = 6543.861 J/mol = 6.544 kJ/mol

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Read more on Brainly.com - brainly.com/question/5143785#readmore

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