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kodGreya [7K]
3 years ago
14

You and some friends visit the Florida State Fair and decide to play a game. To play the game you must slide a metal hockey-type

puck up a wooden ramp so that it drops through a hole at the top of the ramp. Your prize, if you win, is a large, stuffed gorilla. You realize the secret to winning is giving the puck just enough velocity at the bottom of the ramp to make it to the hole. You estimate the distance from the bottom of the ramp to the hole at about 3 m, and the ramp appears to be inclined with an angle of 10o from the horizontal. You just got out of physics class and recall the coefficient of static friction between steel and wood is 0.1 and the coefficient of kinetic friction between steel and wood is 0.08. The mass of the puck is about 1 kg. You decide to impress your friends by sliding the puck at the precise speed on the first try so as to land it in the hole. You slide the puck at 2.0 m/sec. Do you win the stuffed poodle? Let g = 10 m/s2. Note: A slightly too hard throw will win since your aim is so good the puck would drop in the hole.
Physics
1 answer:
frez [133]3 years ago
8 0

I kissed spongebob on the lips omg

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An 67-kg jogger is heading due east at a speed of 2.3 m/s. A 70-kg jogger is heading 61 ° north of east at a speed of 1.3 m/s. F
ololo11 [35]

Answer

given,

mass of jogger  = 67 kg

speed in east direction = 2.3 m/s

mass of jogger 2 = 70 Kg

speed  = 1.3 m/s  in  61 ° north of east.

jogger one

P_1 = m_1 v_1 \hat{i}

P_1 = 67 \times 2.3\hat{i}

P_1 = 154.1 \hat{i}

P_2 = m_2 v_2 \hat{i} +m_2 v_2 \hat{j}

P_2 = 70\times v cos \theta \hat{i} +70\times v sin \theta \hat{j}

P_2 = 70\times 1.3 cos 61^0 \hat{i} +70\times 1.3 sin 61^0\hat{j}

P_2 = 44.12\hat{i} +79.59\hat{j}

now

P = P₁ + P₂

P = 198.22 \hat{i} +79.59 \hat{j}

magnitude

P = \sqrt{198.22^2 + 79.59^2}

P =213.60 kg.m/s

\theta = tan^{-1}\dfrac{79.59}{198.22}

\theta = 21.87

the angle is \theta = 21.87 north of east

7 0
4 years ago
A capacitor of 30.0 μ F 30.0 μF and a resistor of 110 Ω 110 Ω are quickly connected in series to a battery of 4.00 V. 4.00 V. Wh
Tanzania [10]

Answer:Q=31.368\ \mu C

Explanation:

Given

capacitance C=30\ muF

Resistance R=110\ Omega

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t=0.001\ s

Charge on Capacitor in a R-C circuit is given by

Q=Q_0(1-e^{\frac{-t}{RC}})

Q=CV(1-e^{\frac{-t}{RC}})

Q=30\times 10^{-6}\times 4(1-e^{\frac{-0.001}{110\times 30\times 10^{-6}}})

Q=120\times 10^{-6}\times 0.2614

Q=31.368\ \mu C

8 0
4 years ago
I need help with number 2 pls it’s a quiz grade
Eduardwww [97]
2 is correct hope you get it right
8 0
3 years ago
Its mass is 20 grams, and its density is 7.87 g/cm3. What’s the larger cube’s volume?
Alik [6]
Volume = mass / density
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Volume = 2.54 (2 s.f)
3 0
3 years ago
What fraction of the space within the atom is occupied by the nucleus?
ValentinkaMS [17]

Answer:

Approximately 6.8 x 10⁻¹⁵

Explanation:

To be able to get this fraction, there are some things we need to know.

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3. Volume of sphere = V1/V2 = (R1/R2)^3

4. 1 picometer (pm) = 10^-10 cm

CHECK ATTACHMENT FOR Step by step solution to the answer

3 0
3 years ago
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