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3 years ago

What comes down but never goes up

Physics

1 answer:

White raven [17]3 years ago

5 0

Answer:

Explanation:

rain and your age

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You've recently read about a chemical laser that generates a 20.0-cm-diameter, 22.0 MW laser beam. One day, after physics class,

Setler [38]

Answer:

0.3847 m/s

Explanation:

$I$ = Intensity = $\dfrac{P}{A}=\dfrac{P}{\pi r^2}$

d = Diameter = 20 cm

r = Radius = $\dfrac{d}{2}=\dfrac{20}{2}=10\ cm$

c = Speed of light = $3\times 10^8\ m/s$

s = Distance = 100 m

P = Power = 22 MW

Pressure due to the laser is given by

$P_r=\dfrac{I}{c}\\\Rightarrow P_r=\dfrac{P}{Ac}\\\Rightarrow P_r=\dfrac{P}{\pi r^2c}\\\Rightarrow P_r=\dfrac{22\times 10^{6}}{\pi 0.1^2\times 3\times 10^8}\\\Rightarrow P_r=2.33427\ N/m^2$

Force is given by

$F=P_rA\\\Rightarrow F=2.33427\times \pi 0.1^2\\\Rightarrow F=0.07333\ N$

Acceleration is given by

$a=\dfrac{F}{m}\\\Rightarrow a=\dfrac{0.07333}{99}\\\Rightarrow a=0.00074\ m/s^2$

Speed of the block would be

$v=\sqrt{2as}\\\Rightarrow v=\sqrt{2\times 0.00074\times 100}\\\Rightarrow v=0.3847\ m/s$

The speed of the block is 0.3847 m/s

5 0

3 years ago

An astronaut is in space with a baseball and a bowling ball. The astronaut pushes both objects in the same direction. If both ba

Crazy boy [7]

Answer:

As a mass greater than that of baseball, at the moment of the bowling wave the moment of the baseball ball is also greater

Explanation:

This problem is an application of momentum and momentum. When the astronaut pushed balls, he needed more force to move the ball of greater mass (bowling). The expression for soul is

p = m v

Besibol Blade

p1 = m1 v

Bowling ball

p2 = m2 v

As a mass greater than that of baseball, at the moment of the bowling wave the moment of the baseball ball is also greater

p2 >> p1

3 0

4 years ago

A mixture of N2, H2 and He have mole fractions of 0.25, 0.65, and 0.10, respectively. What is the partial pressure of N2 if the

matrenka [14]

Answer: The partial pressure of $N_2$ if the total pressure of the mixture is 3.9 atm is 0.975 atm

Explanation:

According to Raoult's law, the vapor pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the vapor pressure of that component in the pure state.

$p_A=x_A\times P_T$