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zalisa [80]
4 years ago
14

A 120 kg hoop rolls along a horizontal floor so that the hoop's center of mass has a speed of 0.220 m/s. How much work must be d

one on the hoop to stop it?
Physics
1 answer:
jeka57 [31]4 years ago
5 0

Answer:W = -5.808J

Explanation:

Given:

Mass of hoop,m=120kg

Centre of mass speed of hoop,v= 0.220m/s

Rotational inertia,I= mr^2

I=120r^2

Kinetic energy of hoop= Linear kinetic energy + Rotational kinetic energy

K= (1/2mv^2) + (1/2Iw^2)

But w= (v/r)^2

K= (1/2mv^2) + (1/2×120r^2(v/r)^2)

K = (1/2×120×0.220^2) + (1/2×120×0.220^2)

K= 5.808J

To stop the hoop,its final kinetic energy must be zero,

Workdone = Kfinal-Kinitial = 0 - 5.808

W= -5.808J

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Velocity of the bus = 75 miles/hr
Time taken by the bus to travel the distance between two cities = 2.5 hours
Let us assume the distance between the two cities = x
Then
Velocity = Distance/Time taken
Then Distance = Velocity * Time taken
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The distance between the two cities is 187.5 miles.I hope this answer is what you were looking for. This process is applicable for similar problems. In future you can always use this method to determine the answer.

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Water is used to cool down automobile engines when they get hot. Why is water used as a coolant? A. Water is a good conductor. B
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