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marissa [1.9K]
3 years ago
7

You are working for a craft store in the manufacturing department. The craft store does an excellent business selling frames for

artwork, along with accessories. One of the accessories is nonglare glass. When looking at artwork that is mounted behind normal glass, harsh reflections of the light source illuminating the artwork from the front are reflected into the eye of the observer, often obscuring a view of portions of the artwork. Nonglare glass has a thin film on the outside surface that provides destructive interference for light near the center of the visible spectrum. As a result, there is less reflection to obscure your view. Your department has been selling nonglare glass with the minimum possible thickness to create destructive interference for light of wavelength 510 nm. But the store has been receiving complaints that the very thin film is damaged when the glass is rubbed with a cloth and glass cleaner. As a result, your supervisor asks you to determine the next possible thickness of the film (in nm) that will provide the proper destructive interference. The index of refraction of the glass is 1.63 and the index of refraction of the film material is 1.43.
Physics
1 answer:
antoniya [11.8K]3 years ago
4 0

Answer:

Explanation:

For destructive interference in thin films , the condition is

2μ t =( 2n+1)λ/2

where μ is refractive index of thin layer , t is thickness of layer and λ is wave length of light used. In this case for second order thickness n = 1

μ = 1.43 and λ = 510 nm

2μ t = ( 2n+1)λ/2

t =( 2n+1)λ/4μ

= 3 x 510 nm / 4x 1.43

= 267.48  nm

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What is the order of magnitude of the distance of Sun to nearest star in meters?
neonofarm [45]

Answer:

Approximating the Milky Way as a disk and using the density in the solar neighborhood, there are about 100 billion stars in the Milky Way.

Explanation:

Since we are making an order of magnitude estimate, we will make a series of simplifying assumptions to get an answer that is roughly right.

Let's model the Milky Way galaxy as a disk.

The volume of a disk is:

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π

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r

2

⋅

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Plugging in our numbers (and assuming that

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V

=

π

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(

10

21

m

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2

⋅

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10

19

m

)

V

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3

×

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m

3

Is the approximate volume of the Milky Way.

Now, all we need to do is find how many stars per cubic meter (

ρ

) are in the Milky Way and we can find the total number of stars.

Let's look at the neighborhood around the Sun. We know that in a sphere with a radius of

4

×

10

16

m there is exactly one star (the Sun), after that you hit other stars. We can use that to estimate a rough density for the Milky Way.

ρ

=

n

V

Using the volume of a sphere

V

=

4

3

π

r

3

ρ

=

1

4

3

π

(

4

×

10

16

m

)

3

ρ

=

1

256

10

−

48

stars /

m

3

Going back to the density equation:

ρ

=

n

V

n

=

ρ

V

Plugging in the density of the solar neighborhood and the volume of the Milky Way:

n

=

(

1

256

10

−

48

m

−

3

)

⋅

(

3

×

10

61

m

3

)

n

=

3

256

10

13

n

=

1

×

10

11

stars (or 100 billion stars)

Is this reasonable? Other estimates say that there are are 100-400 billion stars in the Milky Way. This is exactly what we found.

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