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Arturiano [62]
2 years ago
8

100 POINTS+BRAINLIEST: 8TH GRADE PHYSICS: “As an object moves away from the center of the earth, the force of gravity INCREASES

OR DECREASES”? Any rude or “for points” answers will get reported. PLEASE HURRY !!!!
Physics
2 answers:
motikmotik2 years ago
7 0

Answer: As you move away from the Earth, the pull of Earth's gravity weakens. Objects have mass and anything that has mass has gravity. The bigger the object, the stronger the force of gravity it exerts.

deff fn [24]1 year ago
3 0

Answer:

Explanation:

Newton's law of gravitational force states that force of gravity is inversely proportional to the distance in between two bodies.

So As an object moves away from the center of the earth, the force of gravity DECREASES.

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If it is triple it means we multiply it by 3 then it is 36.3 m/s/s

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kilogram per mole

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Why is it important for you to understand the basics of organ systems?
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5 0
3 years ago
We push a 38.4-kg box across the floor at constant velocity. If we are pushing a horizontal force of 238 N, find the coefficient
zmey [24]

Answer: 0.62

Explanation:

Coefficient of friction is defined as the ratio of the moving force (Fm) acting on a body to the normal reaction (R).

Note that the normal reaction acts vertically on the object and is equal to the objects weight (W) i.e W=R

Since W = mg, W = 38.4 ×10

W= 384N =R

Normal reaction = 384N

The horizontal force acting on the body will be the moving force which is 238N

Coefficient of friction = Fm/R

Coefficient of friction = 238/384

Coefficient of friction = 0.62

Therefore, coefficient of kinetic friction between the box and the floor is 0.62

5 0
3 years ago
Two sound waves have equal displacement amplitudes, but wave 1 has two-thirds the frequency of wave 2. What is the ratio of the
zlopas [31]

Answer:

\dfrac{I_1}{I_2}=\dfrac{4}{9}

Explanation:

c = Speed of wave

\rho = Density of medium

A = Area

\nu = Frequency

\nu_1=\dfrac{2}{3}\nu_2

Intensity of sound is given by

I=\dfrac{1}{2}\rho c(A\omega)^2\\\Rightarrow I=\dfrac{1}{2}\rho c(A2\pi \nu)^2

So,

I\propto \nu^2

We get

\dfrac{I_1}{I_2}=\dfrac{\nu_1^2}{\nu_2^2}\\\Rightarrow \dfrac{I_1}{I_2}=\dfrac{\dfrac{2}{3}^2\nu_2^2}{\nu_2^2}\\\Rightarrow \dfrac{I_1}{I_2}=\dfrac{4}{9}

The ratio is \dfrac{I_1}{I_2}=\dfrac{4}{9}

8 0
3 years ago
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