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Law Incorporation [45]

4 years ago

11

‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️Please someone find the kindness in their heart to help me!

1 answer:

vredina [299]4 years ago

8 0

PART A

Volume = Area of a triangle base x height (..or length)
Volume = 2,400cm^3
Volume = 1/2(16)(h)(20)
2,400cm^3=1/2(16)(h)(20)
2/400cm^3/160 = 160(h)/160
Part A= 15cm^3=height of the box

PART B

Surface Area = 1/2(15*16)(2)+20(17)(2)+16(20)
Surface Area = 240+680+320
Surface Area = 1,240
Part B = You will need approximately 1,240cm of cardboard.

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3 years ago

I need help asap !!

aleksley [76]

Answer:

Solving the expression $\frac{\sqrt[3]{7} }{\sqrt[5]{7} }$ we get $\mathbf{7^{\frac{2}{15}}}$

Option D is correct option.

Step-by-step explanation:

We need to solve the expression: $\frac{\sqrt[3]{7} }{\sqrt[5]{7} }$

We know that

$\sqrt[3]{x}=x^{\frac{1}{3}$ and $\sqrt[5]{x}=x^{\frac{1}{5}$

<u>Using above rule:</u>

<u /> $\frac{\sqrt[3]{7} }{\sqrt[5]{7} }\\=\frac{7^{\frac{1}{3}}}{7^{\frac{1}{5}}}$ <u />

Now, we know the exponent rule if bases are same and divided then exponents are subtracted i.e: $\frac{a^m}{a^n}=a^{m-n}$ <u />

Using the exponent rule

$=7^{\frac{1}{3}-\frac{1}{5} }\\Simplifying\:exponents\\=7^{\frac{5-3}{15}}\\=7^{\frac{1*5-1*3}{15}}\\=7^{\frac{2}{15}}$

So, solving the expression $\frac{\sqrt[3]{7} }{\sqrt[5]{7} }$ we get $\mathbf{7^{\frac{2}{15}}}$

Option D is correct option.

8 0

3 years ago