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3 years ago

How can you tell that a compound contains an ionic bond

1 answer:

3 0

Is this a scienctif question cuss if so it not only helps u with math there’s a lot of subsists like history math English etc....

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Round to 2 significant numbers, 5239

ohaa [14]

Answer:

Explanation:

Two sig digits means that 5239 becomes 52 with some zeros behind it. How many?

There were 2 numbers after the 2. So two sig digits would become 5200

If the third digit from the left is a 5 or more then the answer would be

5300.

3 0

3 years ago

0.50 mol A, 0.60 mol B, and 0.90 mol C are reacted according to the following reaction

algol [13]

Reactant C is the limiting reactant in this scenario.

Explanation:

The reactant in the balanced chemical reaction which gives the smaller amount or moles of product is the limiting reagent.

Balanced chemical reaction is:

A + 2B + 3C → 2D + E

number of moles

A = 0.50 mole

B = 0.60 moles

C = 0.90 moles

Taking A as the reactant

1 mole of A reacted to form 2 moles of D

0.50 moles of A will produce $\frac{2}{1}$ = $\frac{x}{0.50}$

thus 0.50 moles of A will produce 1 mole of D

Taking B as the reactant

2 moles of B reacted to form 2 moles of D

0.60 moles of B reacted to form x moles of D

$\frac{2}{2}$ = $\frac{x}{0.6}$

x = 2 moles of D is produced.

Taking C as the reactant:

3 moles of C reacted to form 2 moles of D

O.9 moles of C reacted to form x moles of D

$\frac{2}{3}$ = $\frac{x}{0.9}$

= 0.60 moles of D is formed.

Thus C is the limiting reagent in the given reaction as it produces smallest mass of product.

5 0

3 years ago

How many L of 3.0 M H2SO4 solution can be prepared by using 100.0 mL OF 18 M H2SO4?

max2010maxim [7]

Answer: A volume of 600 mL of 3.0 M $H_{2}SO_{4}$ solution can be prepared by using 100.0 mL OF 18 M $H_{2}SO_{4}$ .

Explanation:

Given: $V_{1}$ = ?, $M_{1} = 3.0 M\\$

$V_{2} = 100.0 mL$ , $M_{2} = 18 M$

Formula used to calculate the volume is as follows.

$M_{1}V_{1} = M_{2}V_{2}$

Substitute the values into above formula as follows.

$M_{1}V_{1} = M_{2}V_{2}\\3.0 M \times V_{1} = 18 M \times 100.0 mL\\V_{1} = \frac{18 M \times 100.0 mL}{3.0M}\\= 600 mL$

Thus, we can conclude that a volume of 600 mL of 3.0 M $H_{2}SO_{4}$ solution can be prepared by using 100.0 mL OF 18 M $H_{2}SO_{4}$ .

6 0

3 years ago

Match each item to its proper disposal method. Answers to be used more than once.

salantis [7]

Answer:

1. a)

2. a)

3. b)

4. d)

Explanation:

The disposal method is how we throw away the wastes. In a chemical lab, the correct disposal method guarantees the security of the environment and the humans and animals that may be in contact with the materials.

So:

1. Excess chemical: Because it can be toxic, it may be disposed of in the appropriate waste container, which will depend on the characteristics of the material;

2. Reaction mixture: As the excess chemical, it can be toxic, so it must be disposed of at an appropriate waste container;

3. Used filter paper: Generally, the solids in the filter paper is not toxic, so it can be thrown away in the trash can;

4. Cracked or chipped beaker: Because the beaker is made of glass, it can cut when broken, so it must go to a broken glass box, that will protect the people that will deal with it.

8 0

3 years ago

Water contains 7.0 mg/L of soluble ion (Fe2 ) that is to be oxidized by aeration to a concentration of 0.25 mg/L. The pH of the

SpyIntel [72]

Answer:

For CMFR:

V = 5286 m³

t = 2.6 hr

For PFR:

V = 529 m³

t = 19 minutes

Explanation:

Find attached for the calculation.

4 0

4 years ago