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Soloha48 [4]
3 years ago
12

When changing lanes, you should:

Chemistry
1 answer:
Greeley [361]3 years ago
5 0
The correct answer is A. Adjust your speed to match traffic in the new lane

they want me to use 20 characters haha ignore this down here  
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When you sweat a lot the water content of your blood can drop. Your cells have to maintain a certain level of water and salt in
inn [45]

Answer:

Explanation:

There are key organs and system that assist in ensuring the body maintains homeostasis in the case of water-salt balance.

The excretory system: When one sweats, a lot of water content of the blood can drop (this is what causes the individual to be thirsty). In order to maintain a certain water-salt balance, the excretory system passes some salt out of the body in the form of urine (this is the reason the urine is usually yellowish but small in volume during the summer).

Endocrine system: When water content of the blood drops, vasopressin (also called antidiuretic hormone) is released into the bloodstream stimulating the kidneys to conserve water and release less urine (as said earlier). However, if the body is hydrated, less vasopressin is released and more water is passed in the urine.

5 0
3 years ago
The flask contains 10.0 mL of HCl and a few drops of phenolphthalein indicator. The buret contains 0.150 M NaOH. It requires 21.
masha68 [24]

Answer:

0.321 M

Explanation:

The neutralization reaction of HCl with NaOH is the following:

HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)

So, <u>1 equivalent of HCl</u> reacts with <u>1 equivalent of NaOH</u>. In this case:

1 equivalent HCl = 1 mol HCl

1 equivalent NaOH = 1 mol NaOH

At the equivalence point, the amount of HCl reacts completely with the added amount of titrant (NaOH). As 1 mol of reactant is calculated from the product of the molarity of the solution and the volume, in the equivalent point:

moles HCl = moles NaOH

M(HCl) x V(HCl) = M(NaOH) x V(NaOH)

We have:

M(NaOH) = 0.150 M

V(NaOH) = 21.4 mL = 0.0214 L

V(HCl) = 10.0 mL = 0.01 L

Thus, we calculate the initial concentration HCl as follows:

M(HCl) = (M(NaOH) x V(NaOH))/ (V(HCl))

            = (0.150 M x 0.0214 L)/(0.01 L) = 0.321 M

6 0
3 years ago
Which weigh more 50mL of water or 50 mL of ice
LenKa [72]

Answer:

Water

Explanation:

5 0
3 years ago
What is the answer to question 7, NH4C2H3O2
Sliva [168]
The answer is Ammonium acetate
4 0
3 years ago
Read 2 more answers
Compounds of boron and hydrogen are remarkable for their unusual bonding and also for their reactivity. With the more reactive h
sukhopar [10]

Answer:

Amount of energy released = 1.22\times 10^5\ kJ

Explanation:

For B_2H_6  :-

Mass of B_2H_6  = 4.465 kg = 4465 g ( 1 kg = 1000 g)

Molar mass of B_2H_6  = 27.66 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{4465\ g}{27.66\ g/mol}

Moles\ of\ B_2H_6= 161.42\ mol

From the reaction,

B_2H_6_{(g)} + 6 Cl_2_{(g)}\rightarrow 2 BCl_3_{(g)}+ 6 HCl_{(g)} \Delta\ H_{rxn}=-755.4 kJ

1 mole of B_2H_6 releases 755.4 kJ of energy

161.42 moles of B_2H_6 releases 755.4*161.42 kJ of energy

Amount of energy released = 1.22\times 10^5\ kJ

7 0
3 years ago
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