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pogonyaev
3 years ago
15

An acidic fog in pasadena was found to have a ph of 2.50. which expression represents this ph measurement?

Chemistry
1 answer:
joja [24]3 years ago
5 0

Supposing a temperature of 25 degrees and supposing that all activity coefficients are 1 

pH = -log[H+] 
pOH = -log[OH-] 
pH + pOH = 14 

Thus a pH of 2.50 would mean that the [H+], the concentration of the hydrogen ion, would be 10^(-2.50) 

pH + pOH = 14 
pOH = 14 - pH = 14 - 2.5 = 11.5 
MOH- levels would be coordinated with pOH 
pOH = -log[OH-] ==> [OH-] = [MOH-] = 10^-pOH = 10^-11.5 = 3.2 x 10^-12 

Therefore, MOH¯ = 3.2 × 10¯12 M 

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Answer:

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From the question we are told that

      The pressure of (NO) is P_{NO} = 9.20 \ atm

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       The  pressure of nitrosly chloride (NOCl) is P_{(NOCl)} = 7.70 \ atm

The reaction is

              2NO_{(g)} + Cl_2 (g)    ⇆   2 NOCl_{(g)}

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                    \Delta G^o = 2 \Delta G^o _{NOCl} -   \Delta G^o _{Cl_2}  - 2 \Delta G^o _{NO}

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             \Delta G^o _{Cl_2} = 0kJ/mol

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        \Delta G^o = 2 * 66.1 - 0 - 2 * 87.6

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         Q =  \frac{Pressure \ of  \ product }{ Pressure  \ of \ reactant }

Substituting  values  

        Q = \frac{(7.7)^2 }{(9.2)^2 (9.15) } = \frac{59.29}{774.456}

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           \Delta  G  =  \Delta  G^o  + RT ln Q

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          T is temperature in K  with a given value of  T = 25+273 = 298 K

   Substituting value

                \Delta  G  = -43 *10^{3} + 8.314 *298 * ln [0.0765]

                       = -43-6.36

                      \Delta G = -49.36 kJ

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