Answer:
The second transformation is a rotation around (point) L.
Explanation:
Generally, a rigid transformation is used to change only the position of a figure while the shape remains the same. In order to map a triangle (ΔJKL) to another triangle (ΔMNQ), two rigid transformations were employed. In the first transformation, the vertex L was mapped to the vertex Q. Therefore, the second transformation will definitely involve the rotation around (point) L. This will complete the two rigid transformations.
Answer:
480 g of oxygen.
Explanation:
C3H8 + 5O2 ---> 3CO2 + 4H2O
Using the molar masses:
3*12 + 6*16 g of CO2 were formed from 10*16 g O2
132g g CO2 from 160 g O2
1g CO2 from (160/132) g O2
396 g from (160/132) * 396
= 480 g of oxygen.
Answer : This is not an ideal mixture.
Explanation :
Using Raoult's law :
where,
= total vapor pressure of mixture
= vapor pressure of pure methanol = 256 torr
= vapor pressure of pure water = 55.3 torr
= mole fraction of water = 0.312
= mole fraction of methanol = 1 - 0.312 = 0.688
Now put all the given values in the above formula, we get:
From this we conclude that the total vapor pressure of mixture is less than the total given vapor pressure of 211 torr. That means, the interactions between the methanol and water would be weaker than those between the individual substances. So, this is not an ideal mixture.
Hence, this is not an ideal mixture.
Correct Question :
Mass of water = 50.003g
Temperature of water= 24.95C
Specific heat capacity for water = 4.184J/g C
Mass of metal = 63.546 g
Temperature of metal 99.95°C
Specific heat capacity for metal ?
Final temperature = 32.80°C
In an experiment to determine the specific heat of a metal student transferred a sample of the metal that was heated in boiling water into room temperature water in an insulated cup. The student recorded the temperature of the water after thermal equilibrium was reached. The data we shown in the table above. Based on the data, what is the calculated heat absorbed by the water reported with the appropriate number of significant figures?
Answer:
1642 J
Explanation:
Given:
Mass of water = 50.003g
Temperature of water= 24.95C
Specific heat capacity for water = 4.184J/g C
Mass of metal = 63.546 g
Temperature of metal 99.95°C
Specific heat capacity for metal ?
Final temperature = 32.80° C
To calculate the heat absorbed by water, Q, let's use the formula :
Q = ∆T * mass of water * specific heat
Where ∆T = 32.80°C - 24.95°C = 7.85°C
Therefore,
Q= 7.85 * 50.003 * 4.184
Q = 1642.32 J
≈ 1642 J
