Question

Last week we investigated the black hole at the center of our galaxy, with massMX= 8.5×1036kg. An object whose size is on the order of 1 m (it could beyou!) hangs at a distance from the center of the black hole. At what value of is the tidal force between one end of the object and the other greater thanthe gravitational force attracting the object to the black hole

Answer 1

Answer:

$d=2.38*10^{13}m$

Explanation:

We know the mass of the hole, so we define as,

$M_x= {8.5*10^{36}}$kg

For which centripetal force is equal to gravitational force

$\frac{mv^2}{r}=\frac{GMm}{d^2}$

Angular velocity is equal to v/r,

$w^2r=\frac{6.67*10^{-11}*8.5*10^{36}}{d^2}$

As r=1 and w=1, we clear to d,

$d^2=5.6695*10^{26}$m

$d=2.38*10^{13}m$