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3 years ago

What is the spring constant for a supermarket scale that stretches 0.01 m when a force of 4 N is applied

Physics

1 answer:

bija089 [108]3 years ago

5 0

Answer:

400N/m

Explanation:

K = F/x

= 4/0.01

= 400 N/m

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An object with a mass of 6.5 kg accelerates 12.3 m/s2 when an unknown force is applied to it. What is the amount of the force?

OleMash [197]

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 6.5 × 12.3

We have the final answer as

Hope this helps you

8 0

3 years ago

A parallel-plate capacitor with circular plates of radius 0.19 m is being discharged. A circular loop of radius 0.28 m is concen

aliina [53]

Answer:

$\dfrac{dE}{dt}=2.59\times 10^{12}\ V/m.s$

Explanation:

Given that

R= 0.19 m

r= 0.28 m

I= 2.6 A

We know that

$I_D=\epsilon _oA\dfrac{dE}{dt}$

A= Area of loop

dE/dt= rate of change of electric filed

I=Displacement current

Here r>R

So A=π R²

Now by putting the values

$I=\epsilon _oA\dfrac{dE}{dt}$

$2.6=8.85\times 10^{-12}\times \pi\times 0.19^2\dfrac{dE}{dt}$

$\dfrac{dE}{dt}=2.59\times 10^{12}\ V/m.s$

7 0

4 years ago

5. The force of gravity acting on the object is object’s ______________.

Dima020 [189]

I think it's mass...

The mass of an object refers to the amount of matter that is contained by the object; the weight of an object is the force of gravity acting upon that object. Mass is related to how much stuff is there and weight is related to the pull of the Earth (or any other planet) upon that stuff.

5 0

3 years ago

In an electric vehicle, each wheel is powered by its own motor. The vehicle weight is 4,000 lbs. By regenerative braking, its sp

Slav-nsk [51]

Answer:

the theoretical maximum energy in kWh that can be recovered during this interval is 0.136 kWh

Explanation:

Given that;

weight of vehicle = 4000 lbs

we know that 1 kg = 2.20462

m = 4000 / 2.20462 = 1814.37 kg

Initial velocity $V_{i}$ = 60 mph = 26.8224 m/s

Final velocity $V_{f}$ = 30 mph = 13.4112 m/s

now we determine change in kinetic energy

Δk = $\frac{1}{2}$ m( $V_{i}$ ² - $V_{f}$ ² )

we substitute

Δk = $\frac{1}{2}$ ×1814.37( (26.8224)² - (13.4112)² )

Δk = $\frac{1}{2}$ × 1814.37 × 539.5808

Δk = 489500 Joules

we know that; 1 kilowatt hour = 3.6 × 10⁶ Joule

Δk = 489500 / 3.6 × 10⁶

Δk = 0.13597 ≈ 0.136 kWh

Therefore, the theoretical maximum energy in kWh that can be recovered during this interval is 0.136 kWh

4 0

3 years ago

The elastic extensibility of a piece of string is .08. If the string is 100 cm long, how long will the string be when it is stre

Ksju [112]

Answer:

The elastic extensibility of a piece of string is .08. If the string is 100 cm long, how long will the string be when it is stretched to the point where it becomes plastic? is your ansewer dont take tension

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3 years ago