Answer:
The answer is the 4th one
Explanation:
Good luck man
Complete Question
A uniform electric field of magnitude 144 kV/m is directed upward in a region of space. A uniform magnetic field of magnitude 0.38 T perpendicular to the electric field also exists in this region. A beam of positively charged particles travels into the region. Determine the speed of the particles at which they will not be deflected by the crossed electric and magnetic fields. (Assume the beam of particles travels perpendicularly to both fields.)
Answer:
The velocity is
Explanation:
From the question we are told that
The magnitude of the electric field is 
The magnetic field is 
The force due to the electric field is mathematically represented as

and
The force due to the magnetic field is mathematically represented as

Now given that it is perpendicular , 
=> 
=> 
Now given that it is not deflected it means that

=> 
=> 
substituting values


Answer:
The least efficient light bulb is the first one (25 W - 210 Lumen)
Explanation:
Efficiency can be defined as what you want to obtain over what you need to produce it. In this case Eff= Wattage / Lumen. For each light bulb, their efficiency is: 8.4 / 11.12 / 15.7 Lum/W
Answer:
The time taken for the commercial Jet liner to reach the end of its runway is 10.18 s.
Explanation:
Given;
average acceleration of the commercial Jet liner, a = 3g = 3 x 9.8 m/s² = 29.4 m/s²
distance traveled by the commercial Jet liner, s = 1542 m
The time taken for the commercial Jet liner to reach the end of its runway is calculated as follows;
s = ut + ¹/₂at²
where;
u is the initial velocity of the commercial Jet liner = 0
s = 0 + ¹/₂at²
s = ¹/₂at²
2s = at²

Therefore, the time taken for the commercial Jet liner to reach the end of its runway is 10.18 s.
Answer: 3.63 Nm
Explanation:
from the question we were given the following
mass = 1.7 kg
length of the string (r) = 2.5 ,m
angle θ = 5 degrees
acceleration due to gravity (g) = 9.8 m/s
we can calculate the torque using the formula Torques = m x g x r x sin θ
torque = 1.7 x 9.8 x 2.5 x sin 5
torque = 3.63 Nm