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Diano4ka-milaya [45]
4 years ago
9

At a higher temperature, K = 1.8 × 105. Placing the equilibrium mixture in an ice bath (thus lowering the temperature) will

Chemistry
1 answer:
Soloha48 [4]4 years ago
3 0

The question is incomplete, the complete question is;

1. Given: 2A(g) <-> 2B(g) + C(g). At a particular temperature, K = 1.6x104.

At a higher temperature, K = 1.8x10-5. Placing the equilibrium mixture in an ice bath (thus lowering the temperature) will...

cause [A] to increase

cause [B] to increase

gave no effect

cannot be determined

Answer:

cause [B] to increase

Explanation:

We have to have it behind our minds that;  for an exothermic reaction, when the temperature is increased, the value of the equilibrium constant decreases. On the other hand, for an endothermic reaction, increasing the temperature increases the value of the equilibrium constant.

In this particular case, increasing the temperature decreased the equilibrium constant from K = 1.6x104 to K = 1.8x10-5 meaning that the equilibrium constant decreased with increase in temperature. This means that the reaction is exothermic and a decrease in temperature will favour the forward reaction hence more B is produced.

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Answer:

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Explanation:

Step 1: Data given

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Mass of water = 948.1 grams

Step 2: Convert this value into terms of g/L

(0.210 mol/L) * (342.3 g/mol) = 71.9 g/L

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Mass of the solution = 1000 mL * 1.02 g/mL = 1020 g solution

We know that there are 71.9 g of solute in a liter of solution from the first calculation. This means

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Step 2: Calculate molality

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