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Lunna [17]
3 years ago
8

Help!!! A, B, and C

Chemistry
1 answer:
garik1379 [7]3 years ago
5 0
A. Gold,lead,glass,brick, and steel

b. 8 because they are all over 1.0 density level

c. ice and paraffin (maybe wood but that is not a liquid)<span />
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Name the functional group in the<br> following molecule:
Anna71 [15]

Answer:

B. Aromatic

Explanation:

Functional groups are groups that differentiate a specific organic compound from others. A functional group determines the chemical property of the compound that possesses it.

For example, just like alkene and alcohol functional groups have characteristics double bond (=) and hydroxyl (OH) group respectively, the image in the attachment of this question has a BENZENE RING at the core of its structure, hence, the organic compound can be regarded to have an AROMATIC FUNCTIONAL GROUP.

4 0
3 years ago
When was the idea of a atom first devloped
bija089 [108]

Answer:

Around 450 B.C.

Explanation:

The idea was forgotten until the 1800 when John Dalton re-introduced the atom.

6 0
3 years ago
Using ethanol and sodium or potassium cyanide as the sources of the carbon atoms, along with any necessary inorganic reagents, s
11Alexandr11 [23.1K]

Answer:

Please see attachment

Explanation:

Please see attachment

3 0
3 years ago
For which of the following equilibria does `"K"_("eq") = ["O"_2]`? A. O2(l) O2(g) B. 2O3(g) 3O2(g) C. 2H2O(l) 2H2(g) + O2(g) D.
Feliz [49]

For plato users

the answer is a. O2(l) O2(g)

hope this helps!

8 0
3 years ago
Read 2 more answers
Winter is coming and it's time to make sure you have the right amount of antifreeze
ololo11 [35]

The molality of the solution = 17.93 m

<h3>Further explanation</h3>

Given

6.00 L water with 6.00 L of  ethylene glycol(ρ=1.1132 g/cm³= 1.1132 kg/L)

Required

The molality

Solution

molality = mol of solute/ 1 kg solvent

mol of solute = mol of ethylene glycol

  • mass of ethylene glycol :

= volume x density

= 6 L x 1.1132 kg/L

= 6.6792 kg

= 6679.2 g

  • mol of ethylene glycol (MW=62.07 g/mol)

=mass : MW

=6679.2 : 62.07

=107.608

  • mass of water

6 L water = 6 kg water(ρ= 1 kg/L)

  • molality

\tt =\dfrac{107.608}{6}=17.93~m

5 0
3 years ago
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