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lapo4ka [179]
2 years ago
6

C. Calculate the number of moles in 62g of CO2

Chemistry
2 answers:
Gre4nikov [31]2 years ago
6 0
Number of moles: 62 grams
Molar mass of CO2: 44.01 (we will take it as 44)
Basically: molar mass/moles -> 44/62 ≈ 1.41 .
worty [1.4K]2 years ago
4 0

Answer:

32÷5

I'm just tryna get points I'm sorry

goodluck tho❤

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If you set up an experiment with two different independent variables, then the results would be_____.
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Answer: A) Inconclusive; you would not know which of the two variables caused the change.

Explanation:

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By observing (measuring) the dependent variable, while only one independent variable changes you can understandhow such independent variable explains (determines) the dependent variable, leading to a conclusion.

Conversely, if two or more independent variables change at a time, then there is no way that you can tell how the output (dependent variable) is related with one or other of the changes of the indipendent variables. You wolud not be able to discriminate (distinguish) the effect of one or other variable, making the experiment inconclusive

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4 0
3 years ago
An atom of which of these elements most likely forms an anion? A. AI B. Br C. Ca D. Mg
Papessa [141]
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4 0
3 years ago
Read 2 more answers
What volume is needed to store 0.80 moles of helium gas at 204.6 kpa and 300 k?
shepuryov [24]
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p(He) = 204,6 kPa.
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Use ideal law eqaution: p·V = n·R·T.
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3 0
2 years ago
If you were givin 2.50 moles of.sodium bromide, how many grams of salt do you have
mihalych1998 [28]

Answer: 257.23

Explanation:

7 0
3 years ago
Phosgene (COCl2) is a toxic substance that forms readily from carbon monoxide and chlorine at elevated temperatures: CO(g) + Cl2
lapo4ka [179]

Answer: Concentration of CO = 0.328 M

Concentration of Cl_2 = 0.328 M

Concentration of COCl_2 = 0.532 M

Explanation:

Moles of  CO and Cl_2 = 0.430 mole

Volume of solution = 0.500 L

Initial concentration of CO and Cl_2  =\frac{moles}{volume}=\frac{0.430}{0.500}=0.860M

The given balanced equilibrium reaction is,

                            CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

Initial conc.          0.860M     0.860M           0

At eqm. conc.    (0.860-x) M  (0.860-x) M     (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[COCl_2]}{[CO][Cl_2]}

Now put all the given values in this expression, we get :

4.95=\frac{x}{(0.860-x)^2}

By solving the term 'x', we get :

x =  0.532 M

Thus, the concentrations of CO,Cl_2\text{ and }COCl_2 at equilibrium are :

Concentration of CO = (0.860-x) M =(0.860-0.532) M = 0.328 M

Concentration of Cl_2 =  (0.860-x) M  =  (0.860-0.532) M = 0.328 M

Concentration of COCl_2 = x M = 0.532 M

3 0
2 years ago
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