Are you referring to this question?
All BUT one descriptive phrase applies to the illustration
of water. That is
A) water is a polar molecule.
B) the empirical formula of water is HO.
C) the shape of a water molecule is bent.
D) the molecular formula of water is H2O.
If you are, then the answer would be letter b. the empirical formula of water is HO.<span> </span>
<span>>Water Molecular Formula</span><span>: H</span><span>2</span><span>O</span>
<span>>Water </span>Empirical Formula: H2O
Answer:
mountain and coastal plains
Explanation:
i think it would be coastal plains because the area with low elevation is near the sea. only one answer has coastal plains in it, so use process of elimination. additionally, mountain makes sense since theyre usually steep and end in a peak.
Answer:
The component of water potential due to the hydrostatic pressure that is exerted on water in a cell. ... In turgid plant cells it usually has a positive value as the entry of water causes the protoplast to push against the cell wall (see turgor).
These plants colonize habitats, and exclude the native plants and animals. Since they decrease native biodiversity, they arebad for the environment.
Answer:
D. If all of the offspring are short-tailed, the unknown individual is the homozygous dominant genotype.
Explanation:
The short tail phenotype is completely dominant over the long tail phenotype. When a short tailed salamander with unknown genotype is crossed with a homozygous recessive long tailed salamander, the cross is called testcross. Lets assume that the allele "S" gives "short tail" phenotype while the allele "s" gives "long tail" phenotype.
If the "short tailed salamander" with unknown genotype is homozygous dominant (SS), the process of the testcross will express only dominant trait (cross 1). On the other hand, if the "short tailed salamander" with unknown genotype is heterozygous dominant (Ss), segregation of alleles during gamete formation would form two types of gametes (cross 2). The 50% progeny would express the "long tail" phenotype while rest 50% will express the "short tail" phenotype.
