Endocytosis is a type of bulk transport which involves the movement of large particles through the membrane in and out
Crystal<span> of tetrahedrally bonded carbon atoms in a </span>covalent network lattice<span> witch </span>crystallizes<span> into the diamond </span>lattice.
Moles of K = 32.4/39 = 0.83 mole. According to stoichiometry, 2 moles of K produces 1mole of H2. Therefore, 0.83 mole of K produces = 0.83/2 = 0.415 moles of H2. Therefore number molecules of H2 = moles of H2 x 6.02 x 10^23 = 2.4983 x 10^23 molecules. Hope this helps!
Answer:
The answers are as given in the attachment
Explanation:
The application of the de brogile equation was used and appropriate substitution were made as shown in the attachment
