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3 years ago

What is Nuclear Fission?

2 answers:

8 0

<span>It's where a heavy nucleus splits on its own or upon impact. This will release energy and used in things like bombs, powerplants, etc</span>

SpyIntel [72]3 years ago

7 0

The main process of generating nuclear energy

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Determine the rate of a reaction that follows the rate law rate = k a m b i where

ikadub [295]

(missing part of your question):
when we have K = 1 x 10^-2 and [A] = 2 M & [B] = 3M & m= 2 & i = 1
So when the rate = K[A]^m [B]^i
and when we have m + i = 3 so the order of this reaction is 3 So the unit of K is L^2.mol^-2S^-1
So by substitution:
∴ the rate = (1x 10 ^-2 L^-2.mol^-2S^-1)*(2 mol.L^-1)^2*(3mol.L^-1)
= 0.12 mol.L^-1.S^-1

6 0

4 years ago

Text me lets play imessage gamessssss i need new friends:)<br> 832-525-6333

Sergio [31]

Answer:

Bet texting you right now!

Explanation:

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3 years ago

Read 2 more answers

Give me lil reasoning so I know your not lying for points

ycow [4]

Answer:

0.87 ATM

Explanation:

4 0

3 years ago

The stopcock connecting a 3.06 L bulb containing methane gas at a pressure of 9.61 atm, and a 6.65 L bulb containing oxygen gas

Contact [7]

Answer : The final pressure in the system is 4.22 atm.

Explanation :

First we have to calculate the moles of methane.

$PV=n_1RT$

where,

P = pressure of gas = 9.61 atm

V = volume of gas = 3.06 L

T = temperature of gas = T

$n_1$ = number of moles of methane gas = ?

R = gas constant

Now put all the given values in the ideal gas equation, we get:

$(9.61atm)\times (3.06L)=n_1\times RT$

$n_1=\frac{29.4}{RT}$

Now we have to calculate the moles of oxygen gas.

$PV=n_2RT$

where,

P = pressure of gas = 1.75 atm

V = volume of gas = 6.65 L

T = temperature of gas = T

$n_2$ = number of moles of oxygen gas = ?

R = gas constant

Now put all the given values in the ideal gas equation, we get:

$(1.75atm)\times (6.65L)=n_2\times RT$

$n_2=\frac{11.6}{RT}$

Now we have to determine the final pressure in the system after mixing the gases.

$P_{total}=(n_1+n_2)\times \frac{RT}{V_{total}}$

where,

$P_{total}$ = final pressure of gas = ?

$V_{total}$ = final volume of gas = (3.06 + 6.65)L = 9.71 L

T = temperature of gas = T

R = gas constant

Now put all the given values in the ideal gas equation, we get:

$P_{total}=(\frac{29.4}{RT}+\frac{11.6}{RT})\times \frac{RT}{9.71L}$

$P_{total}=4.22atm$

Therefore, the final pressure in the system is 4.22 atm.

4 0

3 years ago

How does the number of protons compare to the number of<br> electrons in a canton

Tema [17]

Answer: The number of protons in cation is more than the number of electrons

Explanation:

cations are positive ions that means that they lose electrons to be stable nd have electron configuration (atomic number ) equivalent to the preceding noble gas

as : sodium 11 , it loses on electron to be stable and its electron configuration is equivalent to neon 10

so ,the number of protons in cation is more than the number of electrons

i hope it helps!

7 0

3 years ago