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GenaCL600 [577]
3 years ago
15

How does the number of protons compare to the number of electrons in a canton

Chemistry
1 answer:
Tema [17]3 years ago
7 0

Answer: The number of protons in cation is more than the number of electrons

Explanation:

cations are positive ions that means that they lose electrons to be stable nd have electron configuration (atomic number ) equivalent to the preceding noble gas

as : sodium 11 , it loses on electron to be stable and its electron configuration is equivalent to neon 10

so ,the number of protons in cation is more than the number of electrons

i hope it helps!

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How can you get pure water from impure water ? Explain with Experiment ​
crimeas [40]

Answer:

Boil it.

Explanation:

If you mean how to clean water to sanitize it you have to boil it.

3 0
3 years ago
A cylinder with a piston is full of gas which of the following actions would result in an increase in the pressure of the gas be
SpyIntel [72]
The answer is B. Decreasing the cylinder volume decreases the amount of space the gas has to occupy there for increasing pressure
7 0
3 years ago
Copper has two naturally occurring isotopes. Cu−63 has a mass of 62.939 amu and relative abundance of 69.17%.
fiasKO [112]
The answer is 64.907 amu.

The atomic mass of an element is the average of the atomic masses of its isotopes. The relative abundance of isotopes must be taken into consideration, therefore:
atomic mass of copper = atomic mass of isotope 1 * abundance 1 + atomic mass of isotope 2 * abundance 2

We know:
atomic mass of copper = 63.546 amu
The atomic mass of isotope 1 is: 62.939 amu
The abundance of isotope 1 is: 69.17% = 0.6917
The atomic mass of isotope 1 is: x
The abundance of isotope 2: 100% - 69.17% = 30.83% = 0.3083

Thus:
63.546 amu = 62.939 amu * 0.6917 + x * 0.3083
63.546 <span>amu = 43.535 amu + 0.3083x
</span>⇒ 63.546 amu - 43.535 amu = 0.3083x
⇒ 20.011 amu = 0.3083x
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7 0
3 years ago
Balancing chemical equations
kolbaska11 [484]

Answer:

2B2 + 3O2 → 2B2O3

Explanation:

Balance The Equation: B2 + O2 = B2O3

1. Label Each Compound With a Variable

  aB2 + bO2 = cB2O3

2. Create a System of Equations, One Per Element

  B: 2a + 0b = 2c

  O: 0a + 2b = 3c

3. Solve For All Variables (using substitution, gauss elimination, or a calculator)

  a = 2

  b = 3

  c = 2

4. Substitute Coefficients and Verify Result

  2B2 + 3O2 = 2B2O3

      L R

  B: 4 4 ✔️

  O: 6 6 ✔️

hope this helps!

7 0
3 years ago
Which of the following is a method for separating a mixture
Karo-lina-s [1.5K]

A) Using paper chromatography to separate pigments by density


5 0
3 years ago
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