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lana66690 [7]
3 years ago
8

A. element with the highest electronegativity.

Chemistry
2 answers:
tekilochka [14]3 years ago
5 0
Fluorine is the answer I believe
Bess [88]3 years ago
3 0

Answer:

Fluorine

Explanation:

Fluorine is assigned the oxidation number of -1 because it attracts the electrons in the bond more strongly than carbon does. Fluorine appears to have an extra electron, -1 oxidation number.

Fluorine is the most electronegative element on the periodic table.

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How to calculate density (what’s the formula) <br> density=_ divided by _
Sphinxa [80]

Answer:

density equals weigt divided by volume

Explanation:

density =  \frac{m}{v}

8 0
4 years ago
If hydrogen is the lightest element, why don't we use it to inflate balloons
Lubov Fominskaja [6]
Its unstable and flammable... the Hindenberg used it... we saw how that went
3 0
3 years ago
Read 2 more answers
Can anybody help??
kvv77 [185]

The amount of heat energy added to silver to heat it from 25°C to 100°C is :

8737.5 J

<u>Given data: </u>

mass of silver ( m ) = 500 g

T1 = 25°C

T2 = 100°C

s ( specific heat of silver ) = 0.233 J/g.c

<h3 /><h3>Determine the amount of heat required </h3>

Applying the formula below for heat ( Q )

Q = ms * ΔT

   = 500 * 0.233 * ( 100 - 25 )

   = 8737.5 J

Hence we can conclude that the The amount of heat energy added to silver to heat it from 25°C to 100°C is :  8737.5 J.

Learn more about heat energy : brainly.com/question/13439286

5 0
3 years ago
which term describes an educated guess based on observation and background research of a topic? a. conclusion b. hypothesis c. l
strojnjashka [21]
It is either a or b. Hope this helps...
5 0
4 years ago
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The enthalpy of combustion of n-octane, C8H18, is –4.79 × 107 J/kg. What is the enthalpy of combustion expressed in kJ/g?
SIZIF [17.4K]

Answer:

47,9 kJ/g

Explanation:

The enthalpy of combustion is the change in energy due the reaction of combustion of n-octane. If the enthalpy is -4,79x10⁷ J/kg And knowing (1000J = 1kJ) (1000g = 1kg). The enthalpy of combustion expressed in kJ/g is:

-4,79x10^7J/kg \frac{1kJ}{1000J} \frac{1kg}{1000g} = <em>47,9kJ/g</em>

<em></em>

I hope it helps!

6 0
4 years ago
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