B) 0.50 moles of carbon dioxide.
Answer:
Silk worm
Explanation:
Silk worms are boiled and the silk around them is removed
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➷Osmosis is a process by which molecules of a solvent tend to pass through a semipermeable membrane from a less concentrated solution into a more concentrated one, thus equalizing the concentrations on each side of the membrane.
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TROLLER
Answer:
- <em>The solution expected to contain the greatest number of solute particles is: </em><u>A) 1 L of 1.0 M NaCl</u>
Explanation:
The number of particles is calculated as:
a) <u>For Ionic compounds</u>:
- molarity × volume in liters × number of ions per unit formula.
b) <u>For covalent compounds</u>:
- molarity × volume in liters
The difference is a factor which is the number of particles resulting from the dissociation or ionization of one mole of the ionic compound.
So, calling M the molarity, you can write:
- # of particles = M × liters × factor
This table show the calculations for the four solutions from the list of choices:
Compound kind Particles in solution Molarity # of particles
(dissociation) (M) in 1 liter
A) NaCl ionic ions Na⁺ and Cl⁻ 1.0 1.0 × 1 × 2 = 2
B) NaCl ionic ions Na⁺ anc Cl⁻ 0.5 0.5 × 1 × 2 = 1
C) Glucose covalent molecules 0.5 0.5 × 1 × 1 = 0.5
D) Glucose covalent molecules 1.0 1.0 × 1 × 1 = 1
Therefore, the rank in increasing number of particles is for the list of solutions given is: C < B = D < A, which means that the solution expected to contain the greatest number of solute particles is the solution A) 1 L of 1.0 M NaCl.
Answer:
The molar mass of the compound given is 182.182 g/mol.
Explanation:
To calculate the molar mass of the compound, we must multiply the number of moles of each element by the the individual molar mass of each element and add them together.
Let's start with Calcium. The molar mass of Calcium is 40.078. In this compound, we have three moles of Calcium, so we should multiply this number by 3.
40.078 g/mol * 3 mol = 120.234 g
Now, let's do the same for Phosphorus.
30.974 g/mol * 2 g/mol = 61.948 g
To find the molar mass of the entire compound, we should add these two values together.
120.234 g + 61.948 g = 182.182 g
Therefore, the correct answer is 182.182 g/mol.
Hope this helps!
