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gizmo_the_mogwai [7]
3 years ago
7

A sample of gas is at 273°K and 2.00 atm with a volume of 6.00 liters. When the gas is compressed to 3.00 liters and the pressur

e increases to 3.00 atm, what is the new temperature of the sample?
Chemistry
1 answer:
horrorfan [7]3 years ago
3 0

Answer: 0.00488K

Explanation: using the general gas equation

(P1V1)/T1 =(P2V2)/T1

Substitute

2*6/273= 3*3/T

Simplify

T= 0.00488°K

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Lt takes 4 hr 39 min for a 2.00-mg sample of radium-230 to decay to 0.25 mg. what is the half-life of radium-230?
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Radioactive decay => C = Co { e ^ (- kt) |

Data:

Co = 2.00 mg
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t = 4 hr 39 min

Time conversion: 4 hr 39 min = 4.65 hr

1) Replace the data in the equation to find k

C = Co { e ^ (-kt) } => C / Co = e ^ (-kt) => -kt = ln { C / Co} => kt = ln {Co / C}

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2) Use C / Co  = 1/2 to find the hallf-life

C / Co = e ^ (-kt) => -kt = ln (C / Co)

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t = ln(2) / 0.44719 = 1.55 hr.

Answer: 1.55 hr
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