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gizmo_the_mogwai [7]
4 years ago
7

A sample of gas is at 273°K and 2.00 atm with a volume of 6.00 liters. When the gas is compressed to 3.00 liters and the pressur

e increases to 3.00 atm, what is the new temperature of the sample?
Chemistry
1 answer:
horrorfan [7]4 years ago
3 0

Answer: 0.00488K

Explanation: using the general gas equation

(P1V1)/T1 =(P2V2)/T1

Substitute

2*6/273= 3*3/T

Simplify

T= 0.00488°K

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p₁V₁/T₁ = p₂V₂/T₂            Multiply each side by T₁

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Calculations:

(a) Convert <em>temperatures to kelvins </em>

T₁ = (27.0 + 273.15) K = 300.15 K

T₂ = (-8.8 + 273.15) K = 264.35 K

(b) Calculate the<em> pressure </em>

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