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gizmo_the_mogwai [7]
4 years ago
7

A sample of gas is at 273°K and 2.00 atm with a volume of 6.00 liters. When the gas is compressed to 3.00 liters and the pressur

e increases to 3.00 atm, what is the new temperature of the sample?
Chemistry
1 answer:
horrorfan [7]4 years ago
3 0

Answer: 0.00488K

Explanation: using the general gas equation

(P1V1)/T1 =(P2V2)/T1

Substitute

2*6/273= 3*3/T

Simplify

T= 0.00488°K

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How many grams of NaCl are required to make 150.0mL of a 5.000 m solution
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The  number of  grams of NaCl  required  to make 150.0 ml of a 5.000m solution  is  43.875  grams


<u><em>calculation</em></u>

Step 1:  calculate  moles of NaCl

moles=  molarity x  volume in liters

volume in liters =  150.0  ml/1000= 0.15  l

moles is=  5.000mol/l  x0.15  l  =0.75  moles


Step2 :  find  mass

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4 years ago
A chemist adds of a M calcium sulfate solution to a reaction flask. Calculate the mass in grams of calcium sulfate the chemist h
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1.23 g

Explanation:

<em>A chemist adds 1.55 L of a 0.00582 M calcium sulfate solution to a reaction flask. Calculate the mass in grams of calcium sulfate the chemist has added to the flask.</em>

Step 1: Given data

  • Volume of the solution (V): 1.55 L
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Step 2: Calculate the moles (n) of calcium sulfate added

We will use the following expression.

n = C × V

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The molar mass of calcium sulfate is 136.14 g/mol.

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