Answer:
the Glancing angle is the angle between the incident ray and plane mirror which is 90o in the given case. The angle between the direction of the incident ray and the reflected ray is the angle of deviation. Since the angle of deviation for a plane mirror is twice the glancing angle, the angle of deviation is 1800.
Answer:
here: "salt and sugar"
Explanation:
I dunno, looks pretty, gives 5 points. even tough any context is missing
but seriously:
salt and sugar look the same. just someone with a split personality
Answer:
Answer is 'B' I think
Explanation:
Rutherford's Gold Foil Experiment proved the existence of a small massive center to atoms, which would later be known as the nucleus of an atom. Through previous experiments of shooting alpha particles, Rutherford knew they had considerable mass and speed.
Answer:
c = 0.898 J/g.°C
Explanation:
1) Given data:
Mass of water = 23.0 g
Initial temperature = 25.4°C
Final temperature = 42.8° C
Heat absorbed = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Specific heat capacity of water is 4.18 J/g°C
ΔT = 42.8°C - 25.4°C
ΔT = 17.4°C
Q = 23.0 g × × 4.18 J/g°C × 17.4°C
Q = 1672.84 j
2) Given data:
Mass of metal = 120.7 g
Initial temperature = 90.5°C
Final temperature = 25.7 ° C
Heat released = 7020 J
Specific heat capacity of metal = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 25.7°C - 90.5°C
ΔT = -64.8°C
7020 J = 120.7 g × c × -64.8°C
7020 J = -7821.36 g.°C × c
c = 7020 J / -7821.36 g.°C
c = 0.898 J/g.°C
Negative sign shows heat is released.
Answer:
The final volume of the cylinder is 1.67 L
Explanation:
Step 1: Data given
Initial volume = 0.250 L
external pressure = 2.00 atm
Expansion does 288 J of work on the surroundings
Step 2: Definition of reversible work:
Wrev = -P(V2-V1) = -288 J
The gas did work, so V2>V1 (volume expands) and the work has a negative sign.(Wrev<0)
V2 = (-Wrev/P) + V1
⇒ with Wrev = reverse work (in J)
⇒ with P = the external pressure (in atm)
⇒ with V1 = the initial volume
We can see that your pressure is in atm and energy in J
To convert from J to L * atm we should use a convenient conversion unit using the universal gas constants :
R
=
8.314472 J/mol
*K and R= 0.08206 L*atm/K*mol
V2 =- (-288 J * (0.08206 L*atm/K*mol /8.314 J/mol
*K))/2.00 atm + 0.250L
V2 = 1.67 L
The final volume of the cylinder is 1.67 L
