Can some answer this?

How will you separate a solution of benzene and chloroform?

Troyanec [42]

Answer:

$\huge\boxed{\sf Distillation}$

Explanation:

State of benzene at RTP = liquid
State of chloroform at RTP = liquid
Boiling point of benzene = 80.1 °C
Boiling point of chloroform = 61.2 °C

Since, both of the chemicals are liquids, we can separate it by the process of distillation.

<u>Distillation:</u>

is the process in which we separate two liquids on the basis of their difference in boiling points.

<u>How it works:</u>

Since chloroform has less boiling point, it will evaporate and collected first and benzene will follow it after sometime.

- Apparatus of distillation is in the attached file.

$\rule[225]{225}{2}$

7 0

2 years ago

A neutral atom has 8 electrons and 8 neutrons. Which of the following correctly represents the atom? A) carbon-16 B) oxygen-16 C

bija089 [108]

Answer:

D

Explanation:

Oxygen is the 8th element in the periodic table. This means that oxygen has 8 protons and 8 electrons. In order to get the number of neutrons you take the atomic weight in this case 15.9999~16 and you subtract it by the number of protons (16-8).

6 0

4 years ago

Read 2 more answers

What is the free energy change if the ratio of the concentrations of the products to the concentrations of the reactants is 22.3

snow_lady [41]

The free energy change(Gibbs free energy-ΔG)=-8.698 kJ/mol

<h3>Further explanation</h3>

Given

Ratio of the concentrations of the products to the concentrations of the reactants is 22.3

Temperature = 37 C = 310 K

ΔG°=-16.7 kJ/mol

Required

the free energy change

Solution

Ratio of the concentration : equilbrium constant = K = 22.3

We can use Gibbs free energy :

ΔG = ΔG°+ RT ln K

R=8.314 .10⁻³ kJ/mol K

$\tt \Delta G=-16.7~kJ/mol+8.314.10^{-3}\times 310\times ln~22.3\\\\\Delta G=-8.698~kJ/mol$

8 0

4 years ago

Upon adding solid potassium hydroxide pellets to water the following reaction takes place: KOH(s) → KOH(aq) + 43 kJ/mol Answer t

nekit [7.7K]

Answer:

a) Warmer

b) Exothermic

c) -10.71 kJ

Explanation:

The reaction:

KOH(s) → KOH(aq) + 43 kJ/mol

It is an exothermic reaction since the reaction liberates 43 kJ per mol of KOH dissolved.

Hence, the dissolution of potassium hydroxide pellets to water provokes that the beaker gets warmer for being an exothermic reaction.

The enthalpy change for the dissolution of 14 g of KOH is:

$n = \frac{m}{M}$

<u>Where:</u>

m: is the mass of KOH = 14 g

M: is the molar mass = 56.1056 g/mol

$n = \frac{m}{M} = \frac{14 g}{56.1056 g/mol} = 0.249 mol$

The enthalpy change is:

$\Delta H = -43 \frac{kJ}{mol}*0.249 mol = -10.71 kJ$

The minus sign of 43 is because the reaction is exothermic.

I hope it helps you!

5 0

3 years ago

Which gas law would you use for the following problem: What pressure is required to hold 8.0 moles of oxygen gas in an 8.0 L con

emmainna [20.7K]

Answer:

Ideal Gas Law ( PV = nRT)

Explanation:

Using the Ideal Gas Law, we have; PV = nRT

Where P= Pressure = ?

V= Volume = 8.0 L

n = moles = 8.0

R = Gas constant = 0.0821 L.atm/mol/K

T = 80° c + 273 = 353.15K

Therefore Pressure would be; P = nRT/ V = 8 x 0.0821 x 353.15 / 8 = 28.9atm

5 0

3 years ago