To draw a complete lewis structure of one molecule of water, how many electrons must be shown?
2 answers:
Answer:
Total 8 electrons.
Explanation:
To draw a complete lewis structure in water molecule we will calculate the total number of valence electrons
Valence electrons:
Two hydrogen atoms: 2 valence electrons (one each)
One oxygen atom : 6 valence electrons
So total there will be 8 electrons that must be shown in the structure.
Out of these 8, four will be involved in two covalent bonds
Rest four will be in the form of two lone pair of electrons on oxygen atom.
In the Lewis structure, each single bond drawn between elements contain two electrons. The electron dots represent the lone pairs. These are the electrons that take part in the reaction. To obey the octet rule, the oxygen must have eight electrons around it. The hydrogen is exempted from this rule. Therefore, you have to show two electrons.
You might be interested in
Answer:
Velocity, u = 14.7 m/s
Explanation:
It is given that, a driver can probably survive an acceleration of 50 g that lasts for less than 30 ms, but in a crash with a 50 g acceleration lasting longer than 30 ms, a driver is unlikely to survive.
Let v is the highest speed that the car could have had such that the driver survived. Using a = -50 g and t = 30 ms
Using first equation of kinematics as :
In case of crash the final speed of the driver is, v = 0
u = 14.7 m/s
So, the highest speed that the car could have had such that the driver survived is 14.7 m/s. Hence, this is the required solution.