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Step2247 [10]
3 years ago
11

To draw a complete lewis structure of one molecule of water, how many electrons must be shown?

Chemistry
2 answers:
Ipatiy [6.2K]3 years ago
6 0

Answer:

Total 8 electrons.

Explanation:

To draw a complete lewis structure in water molecule we will calculate the total number of valence electrons

Valence electrons:

Two hydrogen atoms: 2 valence electrons (one each)

One oxygen atom : 6 valence electrons

So total there will be 8 electrons that must be shown in the structure.

Out of these 8, four will be involved in two covalent bonds

Rest four will be in the form of two lone pair of electrons on oxygen atom.

love history [14]3 years ago
5 0
In the Lewis structure, each single bond drawn between elements contain two electrons. The electron dots represent the lone pairs. These are the electrons that take part in the reaction. To obey the octet rule, the oxygen must have eight electrons around it. The hydrogen is exempted from this rule. Therefore, you have to show two electrons.

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Antimony has 2 naturally occurring isotopes. The mass of antimony-121 is 120.904 amu and the mass of antimony-123 is 122.904 amu
Sav [38]
Wow, now this one is a hard one, took me quite a while to figure it out but here it is:
120.904(x)+122.904(1-x)=121.76 \\ 
120.904x-122.904x+122.904=121.76 \\ 
-2x+122.904=121.76 \\ 
-2x=-1.144 \\ 
x=.572  \\ 
1-.572=.428
The abundances of the two isotopes is:
Antimony-121 = 57.2%
Antimony-123 = 42.8%
6 0
4 years ago
Does anyone understand this at all??
kolezko [41]

The awnser is absorption

6 0
3 years ago
Read 2 more answers
The solubility of calcium oxalate, CaC2O4, in pure water is 4.8 × 10‑5 moles per liter. Cal­culate the value of Ksp for silver c
inn [45]

Answer:

2.3 × 10⁻⁹

Explanation:

Step 1: Write the reaction for the solution of calcium oxalate

CaC₂O₄(s) ⇄ Ca²⁺(aq) + C₂O₄²⁻(aq)

Step 2: Make an ICE chart

We can relate the molar solubility (S) with the solubility product constant (Ksp) through an ICE chart.

        CaC₂O₄(s) ⇄ Ca²⁺(aq) + C₂O₄²⁻(aq)

I                                0                 0

C                              +S               +S

E                                S                 S

The solubility product constant is:

Ksp = [Ca²⁺] × [C₂O₄²⁻] = S² = (4.8 × 10⁻⁵)² = 2.3 × 10⁻⁹

4 0
3 years ago
Which particle has no mass and no charge?<br> O alpha<br> O beta<br> gamma<br> O<br> neutron
Olegator [25]

Answer:

Neutrons

Explanation:

6 0
3 years ago
Determine the oh of a solution that is 0.220 m in hco3
ICE Princess25 [194]

Answer : The hydroxide ion concentration of a solution is, 5\times 10^{-14}

Explanation :

As we know that HCO_3^- dissociates in water to give hydrogen ion (H^+) and carbonate ion (CO_3^{2-}).

As, 1 mole of HCO_3^- dissociates to give 1 mole of hydrogen ion (H^+)

Or, 1 M of HCO_3^- dissociates to give 1 M of hydrogen ion (H^+)

So, 0.200 M of HCO_3^- dissociates to give 0.200 M of hydrogen ion (H^+)

Now we have to calculate the hydroxide ion concentration.

As we know that:

[H^+][OH^-]=1\times 10^{-14}

0.200\times [OH^-]=1\times 10^{-14}

[OH^-]=5\times 10^{-14}

Therefore, the hydroxide ion concentration of a solution is, 5\times 10^{-14}

6 0
4 years ago
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