Answer: 2.749 x 10^-14
Explanation:
<u>Given:</u>
The concentration of Ce(IO3)4 in the solution = 1.5 x 10-2 g/100 mL= 0.15 g/1000 mL= 0.15 g/L
Molar mass of Ce(IO3)4 = 839.7267 g/mol
Therefore, the molarity of Ce(IO3)4 in the solution is given by:

The solubility equilibrium is given by:

Therefore, the solubility product is given by:
![\begin{gathered}K_{s p}=\left[C e^{3+}\right] \cdot\left[I O_{3}^{-}\right]^{3} \\\therefore K_{s p}=\left(1.7863 \times 10^{-4}\right) \times\left(3 \times 1.7863 \times 10^{-4}\right)^{3}\end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7DK_%7Bs%20p%7D%3D%5Cleft%5BC%20e%5E%7B3%2B%7D%5Cright%5D%20%5Ccdot%5Cleft%5BI%20O_%7B3%7D%5E%7B-%7D%5Cright%5D%5E%7B3%7D%20%5C%5C%5Ctherefore%20K_%7Bs%20p%7D%3D%5Cleft%281.7863%20%5Ctimes%2010%5E%7B-4%7D%5Cright%29%20%5Ctimes%5Cleft%283%20%5Ctimes%201.7863%20%5Ctimes%2010%5E%7B-4%7D%5Cright%29%5E%7B3%7D%5Cend%7Bgathered%7D)

400 kg KI
Explanation:
We assume that the density of water is 1 kg/L and it means that 1000 L of water are equal to 1000 kg of water
To solve this question we use the following formula:
concentration / 100 = mass of the dissolved / mass of the solution
mass of the dissolved KI = (concentration × mass of the solution) / 100
mass of the dissolved KI = (40 × 1000) / 100 = 400 kg
Learn more about:
mass percent concentration
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Plastic and wood are both flammable. If there is one option, I would go with wood most
Likely.
Answer:
Explanation
:Both b/c a chemical formula tells you how many and a sketch formula shows how they are bonded together.
Molecular formulas show how many atoms of each element one molecule of a compound contains. Note: Ionic compounds are generally crystalline solids with high melting points. Other compounds, however, have very different properties.
Answer:
The basic rules for naming of organic compounds are :
1. The longest possible carbon chain should include the carbons of double or triple bonds or functional group.For the number of carbon atom, we add prefix as 'meth' for 1, 'eth' for 2, 'prop' for 3, 'but' for 4, 'pent' for 5, 'hex' for 6, 'sept' for 7, 'oct' for 8, 'nona' for 9 and 'deca' for 10.
2. The naming of alkane is done by adding the suffix -ane, alkene by adding the suffix -ene, alkyne by adding the suffix -yne and ketones by adding the suffix -one.;
3. The numbering is done in such a way that the carbon containing the functional group gets the lowest number.While writing the name, the word root is given first , followed by the position of carbon containing the functional group followed by the suffix.
The structure of 3-propyl hex-1-ene is as follows: