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2 years ago

What is the energy of a photon with: a wavelength of 827 nm? What type of radiation is it?

Chemistry

1 answer:

xeze [42]2 years ago

7 0

Explanation:

Given parameters:

Wavelength of photon = 827nm = 827 x 10⁻⁹m

Unknown:

Energy of the photon = ?

Type of radiation = ?

Solution:

The energy of a photon can be derived using the expression below:

E = $\frac{h c}{wavelength}$

h is the Planck's constant = 6.63 x 10⁻³⁴m²kg/s

c is the speed of light = 3 x 10⁸m/s

Insert the parameters and solve;

E = $\frac{6.63 x 10^{-34} x 3 x 10^{8} }{827x 10^{-9} }$

E = 2.4 x 10⁻¹⁹J

Type of radiation:

Near infrared radiation

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klio [65]

Answer:

$Kp=3.07x10^6$

Explanation:

Hello,

In this case, by knowing the given reference reactions, one could rearrange them as follows:

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Consequently, the equilibrium constant is computed as:

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8 0

3 years ago

Plz someone help, really struggling

frez [133]

Answer:

22.9 Liters CO(g) needed

Explanation:

2CO(g) + O₂(g) => 2CO₂(g)

? Liters 32.65g

= 32.65g/32g/mol

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Rxn ratio for CO to O₂ = 2 mole CO(g) to 1 mole O₂(g)

∴moles CO(g) needed = 2 x 1.02 moles CO(g) = 2.04 moles CO(g)

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*Standard Equation => molecular rxn balanced to smallest whole number ratio coefficients is assumed to be at STP conditions (0°C & 1atm).

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