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3 years ago

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Are The Reactions Of Ordinary Molecular Hydrogen Slow Or Rapid ? Why ?

1 answer:

olchik [2.2K]3 years ago

4 0

In nature reactions of ordinary molecular hydrogen are slow since it's a diatomic molecule whose atoms are held together by very strong covalent bonds.The reaction rate of hydrogen varies depending on temperature and the properties of the reactants, for instance under high temperatures above 500°C hydrogen reacts vigorously and with fluorine it reacts explosively even under low temperatures

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Sebastian has a beaker of 100 ml of water and a beaker of 500 ml of water. He is trying to

Sveta_85 [38]

Answer:

The 2 beakers of water will have different boiling points because the boiling point of water is a physical property and the property is independent of the amount of water.

Explanation:

Got 100 on my test

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3 years ago

what is the proper scientific notation for 0.000476? a.0.476 × 10-3 b.4.76 × 10-4 c.47.6 × 10-5 d.476 × 10-6

-BARSIC- [3]

B. 4.75 × 10-4 is the answer

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3 years ago

A sample of pure NO2 is heated to 335 ∘C at which temperature it partially dissociates according to the equation 2NO2(g)⇌2NO(g)+

vodka [1.7K]

The equilibrium constant for the reaction is 0.00662

Explanation:

The balanced chemical equation is :

2NO2(g)⇌2NO(g)+O2(g

At t=t 1-2x ⇔ 2x + x moles

The ideal gas law equation will be used here

PV=nRT

here n= $\frac{w}{W}$ = $\frac{w}{V}$ = density

P = $\frac{density RT}{M}$ density is 0.525g/L, temperature= 608.15 K, P = 0.750 atm

putting the values in reaction

0.75 = $\frac{0.525 x 0.0821 x 608.15 }{M}$

M = 34.61

to calculate the Kc

Kc= $\frac{ [NO] [O2]}{NO2}$

$\frac{1-2x}{1+x}$ x M NO2 + $\frac{2x}{1+x}$ M NO+ $\frac{x}{1+x}$ M O2

Putting the values as molecular weight of NO2, NO,O2

$\frac{46(1-2x) +30(2x)+32x}{1+x}$

34.61= $\frac{46}{1+x}$

x= 0.33

Kc= $\frac{4x^2)x}{1-2x^2}$

putting the values in the above equation

Kc = 0.00662

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3 years ago

Diluting concentrated 1.74M acetic acid to prepare 200 ml of 8M stick solution. What volume of concentrated acid must be used

TiliK225 [7]

<h3>Answer:</h3>

43.5 mL

<h3>Explanation:</h3>

We are given;

Molarity of dilute acetic acid is 1.74 M
Volume of the solution that needs to be prepared is 200 mL
Molarity of the stock solution 8 M

We are required to determine the volume of acid that must be used.

We need to know the dilution formula;
According to the dilution equation;

M1V1 = M2V2

Rearranging the formula;

V1 = M2V2 ÷ M1

= (1.74 M × 200 mL) ÷ 8 M

= 43.5 mL

Therefore, the volume of the concentrated acid that must be added is 43.5 mL

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3 years ago

You are given a cube with the length of 2.5 cm , a width of 2.5 cm , and a height of 2.5 cm. You place it on the scale, and its

kakasveta [241]

Density is equal to the mass divided by the voulme.
So: 2.5 multiplied by 2.5 by 2.5.
Then: 295 divided by 16.625=18.88g/cm to the power 3

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3 years ago