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denis23 [38]
3 years ago
6

How many particles are there in 2.8 moles of CO2

Chemistry
1 answer:
Drupady [299]3 years ago
3 0

Answer:

Moles = Molecules / (6.0221415 x 10^23)

Explanation:

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An organic compound is analyzed, and it has twice as many hydrogen atoms as oxygen atoms. this compound is most likely a _______
Alborosie
For example, monosaccharides:

C₆H₁₂O₆
aldohexoses
ketohexoses

C₃H₆O₃
aldotrioses
ketotrioses

and many others

4 0
3 years ago
Pls help me out with this question!
jeka94
At STP, copper (Cu) would be the only substance here that will exist in the solid state.
4 0
3 years ago
The first energy level which has f orbitals to fill is <br> A. 3 <br> B.4 <br> C.5 <br> D.2
LenaWriter [7]

Answer:

the answer is 4 because 3 just have d orbitals

5 0
3 years ago
Determine the % yield when 7.80 grams of benzene (c6h6) burns in oxygen gas to form 3.00 grams of co2 gas and water vapor.
gogolik [260]
Benzene reacts with O₂ to produce CO₂ and H₂O, i.e.

                           C₆H₆  +  7.5 O₂    →    6 CO₂  +  3 H₂O

According to equation,

    78.11 g (1 mole) C₆H₆ reacts to produce  =  264 g (6 moles) of CO₂

Hence,

      7.80 g C₆H₆ when reacted will produce  =  X g of CO₂

Solving for X,
                                X  =  (7.80 g × 264 g) ÷ 78.11 g

                                X  =  26.36 g of CO₂

Theoretical Yield:
                             26.36 g 
of CO₂ produced is theoretical yield which shows 100% reaction between benzene and oxygen.

Actual Yield:
                   According to statement the actual amount of CO₂ produced is 3.0 g of CO₂.

%age Yield:
      
                %age Yield  =  (Actual Yield ÷ Theoretical Yield) × 100

Putting Values,

                %age Yield  =  (3.00 g ÷ 26.36 g) × 100

                %age Yield  =  11.38 %
3 0
4 years ago
A sample of a gas is in a sealed container. The pressure of the gas is 565 torr , and the temperature is 27 ∘C . If the temperat
Radda [10]

Answer:

P₂ = 647 torr

Explanation:

Given data:

Initial pressure = 565 torr

Initial temperature = 27°C

Final temperature = 71°C

Final pressure = ?

Solution:

Initial temperature = 27°C (27+273 = 300 K)

Final temperature = 71°C (71+273 = 344 K)

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

565 torr / 300K = P₂/344 K

P₂ = 565 torr × 344 K / 300 K

P₂ = 194360 torr. K /293 K

P₂ = 647 torr

5 0
3 years ago
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