<span>(a) what is the average volume (in cubic meters) required for each iron atom
For this case, the density of Iron would be </span>7.87g/cm³
<span>
V = 9.27 x 10^-26 kg / </span>7.87g/cm<span>³ ( 1 kg / 1000 g)
</span>V = 1.18 x 10-23 cm³<span>
(b) what is the distance (in meters) between the centers of adjacent atoms?
We assume the atoms as cube, so we use the volume of the cube to calculate the distance of the atoms.
V = </span>1.18 x 10-23 cm<span>³ = s</span>³
s = 2.28 x 10^-8 cm
yo que se wey nose una particula
Answer:
Enthalpy Change when 1 mole CaCl₂ dissolves
= - 81.13 kj/mole
Explanation:
Given information
Mass of CaCl₂ = 23.6 g
Temperature changes from 25.0°C to 38.7°C
Heat capacity of solution & calorimeter (C) = 1258 J/°C
We know Q = C x ΔT
⇒ Heat released = 1258 x (38.7 - 25)
= 1.7234 x 10⁴ J
= 17.2 Kilo-joule
Thus 23.6 g is equivalent to 1.7234 x 10⁴ J or 17.2 Kilo-joule of heat energy
Molar mass of calcium chloride (110.98)
Enthalpy Change when 1 mole CaCl₂ dissolves
= 
The atoms on the outermost level are called electrons.
The tendency of a moving object to continue moving in a straight line or a stationary object to remain in place is called inertia.
Answer: C) or the third option.
