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Yanka [14]
3 years ago
14

How long is a pendulum with a period of 1.0 s on a planet with twice the gravity of the earth?

Physics
1 answer:
UkoKoshka [18]3 years ago
6 0

Explanation:

T = 2π √(L / g)

1.0 s = 2π √(L / 19.6 m/s²)

L = 0.50 m

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There is a species of bamboo that can grow 36 inches per day. If a plant grew at this rate and was measured at 40 inches initial
LekaFEV [45]

Answer:

It will take the plant 4\frac{4}{9} days or 4.44 days to grow to a height of 200 inches tall.

Explanation:

From the question, the rate at which the species of the bamboo tree grows is 36 inches per day.

To determine how long it would take a plant 40 inches tall initially to grow at this rate (that is, 36 inches per day) to a height of 200 inches.

This means we will calculate the number of days it will take the plant to grow additional 160 inches ( 200 inches - 40 inches) at this rate.

Now,

If the plant grows 36 inches in 1 day

then it will grow 160 inches in x days

x = (160 inches × 1 day) / 36 inches

x = 160 / 36

x = 4\frac{4}{9} days or 4.44 days

Hence, it will take the plant 4\frac{4}{9} days or 4.44 days to grow to a height of 200 inches tall.

8 0
3 years ago
In a crash test, a truck with mass 2100 kg traveling at 22 m/s smashes head-on into a concrete wall without rebounding. The fron
slega [8]

Answer:

a)   v_average = 11 m / s, b)  t = 0.0627 s

, c)    F = 7.37 10⁵ N

, d)   F / W = 35.8

Explanation:

a) truck speed can be found with kinematics

         v² = v₀² - 2 a x

The fine speed zeroes them

           a = v₀² / 2x

           a = 22²/2 0.69

           a = 350.72 m / s²

The average speed is

           v_average = (v + v₀) / 2

           v_average = (22 + 0) / 2

           v_average = 11 m / s

b) The average time

          v = v₀ - a t

          t = v₀ / a

          t = 22 / 350.72

          t = 0.0627 s

c) The force can be found with Newton's second law

             F = m a

             F = 2100 350.72

             F = 7.37 10⁵ N

.d) the ratio of this force to weight

             F / W = 7.37 10⁵ / (2100 9.8)

             F / W = 35.8

.e) Several approaches will be made:

- the resistance of air and tires is neglected

- It is despised that the force is not constant in time

- Depreciation of materials deformation during the crash

5 0
3 years ago
A child is riding a merry-go-round that is turning at 7.18 rpm. if the child is standing 4.65 m from the center of the merry-go-
Alisiya [41]
First we need to convert the angular speed from rpm to rad/s. Keeping in mind that 
1 rev= 2 \pi rad
1 min = 60 s
the angular speed is
\omega = 7.18  \frac{rev}{min} \cdot  \frac{2 \pi}{60} = 0.75 rad/s

And so now we can calculate the tangential speed of the child, which is the angular speed times the distance of the child from the center of the motion:
v= \omega r = (0.75 rad/s)(4.65 m)=3.50 m/s
3 0
4 years ago
Assume that you have two objects, one with a mass of 6 kg and the other with a mass of 17 kg, each with a charge of −0.027 c and
kirill115 [55]
Ken jenr ewjk hfjek kwe hwlr herw hriehr jkwehrt 
3 0
3 years ago
An airplane is sitting on a runway waiting to take off. The airplane begins to move down the runway and it takes 10 s for the ai
Yuliya22 [10]

Acceleration = (change in speed) / (time for the change)

-- You said that the airplane has to speed up from zero ("sitting") to 40 m/s, so the change in speed is 40 m/s.

-- You said that it has to roll for 10 seconds to build up enough speed to take off, so the time for the change is 10 s .

Acceleration = (40 m/s) / (10 s)

Acceleration = (40/10) (m/s)/s

<em>Acceleration = 4 m/s²</em>

That seems like no problem.  It's only like about 41% of 1 G .  That would not even spill the drinks in First Class, or wake up the passengers who are already asleep (like me).

7 0
3 years ago
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