Answer:
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Explanation:
A poem about the scientific method
The chemical contractor has to retrieve the chemical and a identification analysis would have to be conducted
This is all i know
First of all, let's write the equation of the reaction.
CH₃COOH + NaOH ⇒ CH₃COONa + H₂O
The formula to be used here is CaVa/CbVb = na/nb
where Ca is the concentration of the acid (?)
Cb is the concentration of the base (0.175M)
Va is the volume of the acid (25 mL)
Vb is the volume of the base (37.5 mL)
na is the number of moles of acid (1)
nb is the number of moles of base (1)
Ca × 25/0.175 × 37.5 = 1/1
Ca = 0.175 × 37.5 × 1 /25 ×1
Ca = 0.263 M
The concentration of the acid in the sample was 0.263 M
Answer:
The temperature increases from 23.0 C to 37.0 °C
Explanation:
<u>Step 1:</u> Data given
DH = -44.4 kJ/mol
mass NaOH = 13.9 grams
mass of water = 250.0 grams
Initial temperature = 23°C = 295 K
Final temperature = TO BE DETERMINED
Specific heat = 4.18 J/g*K
<u>Step 2: </u>Calculate change in temperature
13.9 grams/ 40 g/mol * 44.4 kJ/mol = 15429 J
15429 J = (massNaOH + mass water) * 4.18 * ΔT
15429 = 263.9 *4.18 * ΔT
ΔT = 14°C
<u>Step 3:</u> Calculate final temperature
ΔT= 14°C = T2 - 23°C
T2 = 23 +14 = 37 °C
The temperature increases from 23.0 C to 37.0 °C
