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Alexxandr [17]
4 years ago
12

Marion is on a train that travels 10 m/s and takes 2 seconds to slow to 5 m/s. How would you correctly calculate the acceleratio

n?
Physics
1 answer:
Rashid [163]4 years ago
7 0

Explanation:

t=2s

u=10

v=5

a=?

v=u+at

5=10+2a

2a=-5

a=-2.5

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A manometer that is filled with water (rho=1000 kg/m3) is connected to a wind tunnel to measure the pressure inside the test sec
Anna [14]

To develop this problem it is necessary to apply the concepts performed to the absolute pressure based on the reference pressure (atmospheric) and the pressure that is generated due to the height of the column of the measured liquid.

In mathematical terms the previous concept can be expressed as

P_{abs} = P_{atm} -\rho gh

Where

P_{atm}=Atmospheric Pressure

\rho =Density

g = Gravitational acceleration

h = Height

Our values are given as

h = 10*10^{-3}m

g = 9.8m/s

\rho_{water} = 1000kg/m^3

P_{atm} = 100kPa

Replacing we have then that

P_{abs} = P_{atm} -\rho gh

P_{abs} = 100 -(1000)(9.8)(10*10^{-3})

P_{abs} = 99.9019kPa

Therefore the absolute pressure in the test section is 99.9019kPa

6 0
3 years ago
At the end of the adiabatic expansion, the gas fills a new volume V₁, where V₁ > V₀. Find W, the work done by the gas on the
tino4ka555 [31]

Answer:

W=\frac{p_0V_0-p_1V_1}{\gamma-1}

Explanation:

An adiabatic process refers to one where there is no exchange of heat.

The equation of state of an adiabatic process is given by,

pV^{\gamma}=k

where,

p = pressure

V = volume

\gamma=\frac{C_p}{C_V}

k = constant

Therefore, work done by the gas during expansion is,

W=\int\limits^{V_1}_{V_0} {p} \, dV

=k\int\limits^{V_1}_{V_0} {V^{-\gamma}} \, dV

=\frac{k}{\gamma -1} (V_0^{1-\gamma}-V_1^{1-\gamma})\\

(using pV^{\gamma}=k )

=\frac{p_0V_0-p_1V_1}{\gamma-1}

4 0
3 years ago
Thermal escape of an atmosphere is most pronounced on worlds where the gravity is low and the temperature is high.
Alona [7]
The answer is false
7 0
4 years ago
You drive your car from home at an
kondaur [170]

Answer:

60 km/h

Explanation:

In the first part of the trip, the speed is

v = 80 km/h

while the time interval is

t = 3 h

So, the distance covered is:

d = vt = (80)(3)= 240 km

The problem states that this distance is half distance between home and the destination - so, the total distance between home and the destination is

D=2d=2(240)=480 km

The time taken to cover the second part of the trip is 5 h, so the total time taken is

T = 3 h + 5 h = 8 h

Therefore, the average velocity for the entire trip is

v=\frac{D}{T}=\frac{480}{8}=60 km/h

3 0
3 years ago
Short-term memory is active, while long-term memory is:
Afina-wow [57]

Answer:

the answer is b. reflective

6 0
3 years ago
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