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3 years ago

What is the main determining factor in defining boundaries between layers of earth's atmosphere?

2 answers:

5 0

The main determining factor in defining boundaries between layers of earth's atmosphere would be temperature changes in these layers. Temperature is one essential property that varies in the atmosphere. Based from this variation, the atmosphere is divided into four major layers and further to three smaller layers - troposphere, tropopause, the stratosphere, stratopause, the mesosphere, mesopause, and the thermosphere.The troposphere is the layer that is nearest to the surface of the Earth. It is the part where humans, plants and animals survive. Also, it is the warmest layer of the atmosphere. And as we go higher the atmosphere, the temperature would drop making it much cooler.

lakkis [162]3 years ago

4 0

Answer:

temperature changes.

Explanation:

Temperature changes with altitude determine the boundaries between layers of Earth’s atmosphere

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The density of sodium is 968 g/cm3. Suppose you need 250 gm of sodium for an experiment. Which volume of sodium do you need?

Masja [62]

The formula for the density of a substance expressed in mass and volume is rho = mass/volume or p = m/v. Rearranging the formula to isolate volume gives the formula v = m/p. To solve for the problem given, this formula must be used. This gives a solution of:

v = m/p = 250 g/ 968 g/cm^3 = 0.258 cm^3 of sodium

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3 years ago

Can a metallic sphere be charged without rubbing

morpeh [17]

We need to charge a metal sphere positively without touching it. This can be achieved using electrostatic induction.

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3 years ago

A rocket for use in deep space is to have the capability of boosting a total load (payload plus the rocket frame and engine) of

choli [55]

Answer:

Explanation:

Let f be the amount of fuel oxidizer needed

v be the speed

The relationship between them is inverse in nature i.e

f ∝ 1/v

f = k/v

If a rocket for use in deep space is to have the capability of boosting a total load (payload plus the rocket frame and engine) of 3.25 metric tons to a speed of 10,000 m/s, then f = 3.25 when v = 10,000

Substitute and get k

k = fv

k = 3.25 * 10,000

k = 32500

To get the amount of fuel oxidizer required to produce a speed of 2400m/s, we will find f when v = 2400m/s

Recall that f = k/v

f = 32500/2400

f = 13.54 metric tons

<em>Hence the fuel plus oxidizer that will be required is 13.54 tons</em>

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3 years ago

A boy kicks a football from ground level. The ball takes 3 seconds to reach its maximum height. What is the angle of the initial

ruslelena [56]

<h2>The angle of the initial velocity with respect to the horizontal is 85.14°</h2>

Explanation:

Given that the ball takes 3 seconds to reach its maximum height.

Consider the vertical motion of ball till maximum height.

We have equation of motion v = u + at

Acceleration, a = -9.81 m/s²

Final velocity, v = 0 m/s

Time, t = 3 s

Substituting

v = u + at

0 = u + -9.81 x 3

u = 29.43 m/s

Initial vertical velocity is 29.43 m/s.

Now consider horizontal motion of ball.

Time of flight of ball = 2 x Time to reach maximum height = 2 x 3 = 6 s

Displacement = 15 m

We have equation of motion s = ut + 0.5 at²

Displacement, s = 15 m

Acceleration, a = 0 m/s²

Time, t = 6 s

Substituting

s = ut + 0.5 at²

15 = u x 6 + 0.5 x 0 x 6²

u = 2.5 m/s

Initial horizontal velocity is 2.5 m/s

Let r be the initial velocity and θ be the angle with horizontal

Initial vertical velocity = rsinθ = 29.43 m/s

Initial horizontal velocity = rcosθ = 2.5 m/s

Dividing

$\frac{rsin\theta }{rcos\theta }=\frac{29.43}{2.5}\\\\tan\theta=11.77\\\\\theta=85.14^0$

The angle of the initial velocity with respect to the horizontal is 85.14°

4 0

3 years ago

an airplane is moving with a constant velocity in level flight. compare the magnitude of the forward force by the engines to the

Iteru [2.4K]

The two forces are equal in magnitude

Explanation:

We can answer this question by applying Newton's second law of motion, which states that

$\sum F = ma$

where

$\sum F$ is the net force acting on an object

m is the mass of the object

a is its acceleration

In this problem, the airplane is moving with constant velocity, so its acceleration is zero:

a = 0

This means that the equation becomes

$\sum F = 0$

There are two forces acting on the airplane in the horizontal direction:

- The forward force exerted by the engine, F

- The frictional drag force, D, backward

So the net force on the plane along the horizontal direction is

$\sum F = F-D$

However we also said that

$\sum F = 0$

Combining the two equations, we find

$F-D=0 \rightarrow F=D$

So, the two forces have same magnitude.

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

5 0

3 years ago