An airplane is flying overhead at a constant elevation of 3000ft. A man is viewing the plane from a position 4000ft from the bas
e of a radio tower. The airplane is flying horizontally away from the man. If the plane is flying at a rate of 500ft/s, at what rate is the distance between the man and the plane increasing when the plane passes over the radio tower?
1 answer:
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Answer:OB=58.3m
Explanation:
So here cow wanders 30m in north and turns 22 degrees in right side and moves 40m more, as shown in figure given.
now take the starting point as a origin such that cow moves in x-y co-ordinate axis.
As shown in figure length OA is the length when cow moves in north or y direction. Later she takes 22 degrees turn to right and moves 40m more.
So the final displacement is the length of cow from the origin that is length OB.
now co-ordinates of B are [40cos22°,40sin22°+30] i.e [37.084,44.984]
now displacement of cow= length of OB
=
=
OB =
The amount of extra electrons present on the negative surface is
57.2 x .
Distance =1.6 cm
Side = 24 cm
Electric field = 18000 N/C
Calculating the capacitance in the metal plates is necessary.
Using the capacitance formula
Putting the value
C = 8.85 x x (24 x
/1.6 x
C = 0.318 x F
V = Ed
V = 18000 x 1.6 x V
V = 288 V
<h3>Calculation of charge</h3>Q = CV
Q = 0.318 x x 288
Q = 91.54 x C
Charge on the both the plates
Q = +91.54 x
Q = - 91.54 x
Calculation of excess electrons on the negative surface:
n = q/e
n = 91.54 x / 1.6 x
n = 57.2 x electrons
Hence, the number of excess electrons on the negative surface is
57.2 x .
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