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Julli [10]
3 years ago
14

A student places a battery in a beaker of salt water and sees bubbles rise from the terminals. Researching which

Chemistry
2 answers:
lara31 [8.8K]3 years ago
7 0

Answer is: D the temperature of the water in each beaker

If you find this helpful, Mark me as brainlyiest!

If this is not the correct answer.. Please correct me!

Troyanec [42]3 years ago
4 0

Answer: What is the composition of the gas bubbles?

Explanation: Test taken and verified the answer.

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6. A. If 4.50 mols of ethane, C2H6, undergoes combustion according to the unbalanced equation
uranmaximum [27]

Answer:

for one mole of C2H6 there are 7/2 mole of O2 required. so for4. 50 moles you require 4.50 x 7/2 = 15.75 moles of O2.

Explanation:

i hope it's helpful

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2 years ago
In the reaction of sodium and oxygen, which atom is the reducing agent?
pishuonlain [190]
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8 0
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Can someone PLEASE HELP me? <br><br> How can you tell if a bond is Covalent?
g100num [7]
There is a couple different ways to determine if a bond is ionic orcovalent. By definition, an ionicbond is between a metal and a nonmetal, and a covalent bond is between 2 nonmetals. So you usually just look at the periodic table and determine whether your compound is made of a metal/nonmetal or is just 2 nonmetals.
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Major species present when fructose is dissolved in water
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7 0
3 years ago
Read 2 more answers
How much heat is required to convert 20.0 g of ice at 50.0⁰C to liquid water at 0.0⁰C? The specific heat of ice is 2.06 J/(g∙⁰C)
Alex777 [14]

Answer:

8740 joules are required to convert 20 grams of ice to liquid water.

Explanation:

The amount of heat required (Q), measured in joules, to convert ice at -50.0 ºC to liquid water at 0.0 ºC is the sum of sensible heat associated with ice and latent heat of fussion. That is:

Q = m\cdot [c\cdot (T_{f}-T_{o})+L_{f}] (1)

Where:

m - Mass, measured in grams.

c - Specific heat of ice, measured in joules per gram-degree Celsius.

T_{o}, T_{f} - Temperature, measured in degrees Celsius.

L_{f} - Latent heat of fussion, measured in joules per gram.

If we know that m = 20\,g, c = 2.06\,\frac{J}{g\cdot ^{\circ}C}, T_{f} = 0\,^{\circ}C, T_{o} = -50\,^{\circ}C and L_{f} = 334\,\frac{J}{g }, then the amount of heat is:

Q = (20\,g)\cdot \left\{\left(2.06\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot [0\,^{\circ}C-(-50\,^{\circ}C)]+334\,\frac{J}{g} \right\}

Q = 8740\,J

8740 joules are required to convert 20 grams of ice to liquid water.

3 0
2 years ago
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