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Julli [10]
3 years ago
14

A student places a battery in a beaker of salt water and sees bubbles rise from the terminals. Researching which

Chemistry
2 answers:
lara31 [8.8K]3 years ago
7 0

Answer is: D the temperature of the water in each beaker

If you find this helpful, Mark me as brainlyiest!

If this is not the correct answer.. Please correct me!

Troyanec [42]3 years ago
4 0

Answer: What is the composition of the gas bubbles?

Explanation: Test taken and verified the answer.

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4.True or false. P(E) + P(Ec) = 1.
iogann1982 [59]
4.) True: 
Since
P(E) = 1 - P(Ec)
P(E)+P(Ec)=1 
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3 years ago
What nation has attempted to drill through Earth's crust?
timofeeve [1]

Answer:

The Soviet Nation attempted to

4 0
2 years ago
What is the density of 0.50 grams of gaseous carbon stored under 1.5 atm of pressure at a temperature of -20.0 C?
Colt1911 [192]

Answer: The density of 0.50 grams of gaseous carbon stored under 1.50 atm of pressure at a temperature of -20.0 °C is 0.867 g/L.

Explanation:

  • d = m/V, where d is the density, m is the mass and V is the volume.
  • We have the mass m = 0.50 g, so we must get the volume V.
  • To get the volume of a gas, we apply the general gas law PV = nRT

P is the pressure in atm (P = 1.5 atm)

V is the volume in L (V = ??? L)

n is the number of moles in mole, n = m/Atomic mass, n = 0.50/12.0 = 0.416 mole.

R is the general gas constant (R = 0.082 L.atm/mol.K).

T is the temperature in K (T(K) = T(°C) + 273 = -20.0 + 273 = 253 K).

  • Then, V = nRT/P = (0.416 mol)(0.082 L.atm/mol.K)(253 K) / (1.5 atm) = 0.576 L.
  • Now, we can obtain the density; d = m/V = (0.50 g) / (0.576 L) = 0.867 g/L.
6 0
3 years ago
While working in the chemistry lab, you dissolve 2.5g of sodium hydroxide chips into a beaker containing 50mL of water. As you p
leva [86]

Answer:

Energy was released when the sodium and hydroxide ions formed new bonds with the water.

Explanation:

4 0
3 years ago
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c. table salt is a metalloid with properties of both reactants

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3 years ago
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